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Php Codeigniter获取数据时出错

php mysql codeigniter

Php Codeigniter获取数据时出错,php,mysql,codeigniter,fetch,Php,Mysql,Codeigniter,Fetch,我用php编写了一个程序，它工作正常（php程序工作正常，而不是codeigniter版本）。现在，我想用Codeigniter制作这个程序 这是我的php程序： <?php include('connect.php'); ?> <html> <head> <script src="http://code.jquery.com/jquery-2.1.1.min.js"></script> <meta

我用php编写了一个程序，它工作正常（php程序工作正常，而不是codeigniter版本）。现在，我想用Codeigniter制作这个程序

这是我的php程序：

    <?php include('connect.php');

?>

<html>
<head>

    <script src="http://code.jquery.com/jquery-2.1.1.min.js"></script>
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap-theme.min.css" integrity="sha384-rHyoN1iRsVXV4nD0JutlnGaslCJuC7uwjduW9SVrLvRYooPp2bWYgmgJQIXwl/Sp" crossorigin="anonymous">
    <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>

</head>
    <body>

    <div class="container"> 
    <div class="row">
    <div class="col-md-12">



    <a href="estudiante.php"><button type="button" class="btn btn-success">AGREGAR</button></a><br /><br />
        <h2 align="center">TABLA:MATERIAS</h2>
        <input id="busqueda_tabla" type="text">
            <table class="table table-hover" align="center" border="1" cellspacing="0" cellpadding="0" width="700" id="tabla_busqueda">
                <thead>
                    <th>id</th>
                    <th>Carrera</th>
                    <th>Nombre</th>
                    <th>Descripcion</th>
                    <th>Carga horaria (hs)</th>
                    <th>Accion</th>
                </thead>

    <?php

                $sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.id");//ESTA FUNCION ME AYUDA A ACOMODAR LAS CARRERAS EN LA COLUMNA "CARRERA" DE LA TABLA
                $i=1;
                    while($row=mysql_fetch_array($sql)){
                        echo "<tr>
                                <td>".$i."</td>
                                <td>".$row['carrera']."</td>
                                <td>".$row['nombre']."</td>
                                <td>".$row['descripcion']."</td>
                                <td>".$row['carga_horaria']."</td>
                                <td align='center'>
                                    <a href='editar.php?editar=1&iden=".$row['id']."'><button type='button' class='btn btn-primary'>EDITAR</button></a> |
                                    <a href='borrar.php?borrar=1&iden=".$row['id']."'><button type='button' class='btn btn-danger'>BORRAR</button></a>
                                </td>
                        </tr>";
                        $i++;

                    }
                ?>


            </table>    

        </div>
        </div>
        </div>

    </body>



</html>
我的数据库和自动加载文件：

https://i.gyazo.com/ef7eb80b6f484e4831b78a3408a05b48.png
https://i.gyazo.com/ecf3de9845ed039f877613ffef4e6aa7.png
不知道该怎么办：/，能帮我弄清楚吗？

使用它

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.carrera_id");
而不是

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.id");
当您将数据从控制器传递到视图时，请将其作为数组传递，而不是简单的变量。
在config/database-all-parameters中检查您的连接。
在控制器中加载页眉和页脚

大副，那一行属于“旧”代码。它工作正常，问题是Codeigniter版本：的重复 
    <?php

    class Home extends CI_Controller{

        public function index(){
            $this->load->model('Crudmodel');
            $data['records'] = $this->Crudmodel->getRecords();
            $this->load->view('home', $data['records']);

        }
    }
?>

https://i.gyazo.com/607303edcd861d0a2257611c925f3e6e.png
https://i.gyazo.com/eb9d833bf5d0818db2906ec1447550c0.png
https://i.gyazo.com/c5bb77d50315888a375a1e775a5ad68c.png

https://i.gyazo.com/ef7eb80b6f484e4831b78a3408a05b48.png
https://i.gyazo.com/ecf3de9845ed039f877613ffef4e6aa7.png

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.carrera_id"); 

$sql=mysql_query("SELECT s.*, c.nombre AS carrera FROM materias s LEFT JOIN carreras c ON s.carrera_id=c.id");