Php jquery表保存到数据库
我正在使用以下代码启用对表格的实时编辑:Php jquery表保存到数据库,php,jquery,Php,Jquery,我正在使用以下代码启用对表格的实时编辑: <script type="text/javascript"> $(document).ready(function(){ var aDataSet = [ ["klad1111.com","<img src='world/se.png' />","-","0","0","0%","0"], ["klad2222.com","<img src='world/dk.png' />","2012-12
<script type="text/javascript">
$(document).ready(function(){
var aDataSet = [
["klad1111.com","<img src='world/se.png' />","-","0","0","0%","0"],
["klad2222.com","<img src='world/dk.png' />","2012-12-05","1","3","300%","15"],
["klad33333.com","<img src='world/dk.png' />","-","0","0","0%","0"],
["klad6666.info","<img src='world/dk.png' />","-","0","0","0%","0"],
["klad44444.info","<img src='world/dk.png' />","-","0","0","0%","0"],
["klad5555.com","<img src='world/se.png' />","-","0","0","0%","0"],
];
$('#dynamic').html( '<table cellpadding="0" cellspacing="0" border="0" class="display" id="example"></table>' );
$('#example').dataTable( {
"aaData": aDataSet,
"aoColumns": [
{ "sTitle": "Namn" },
{ "sTitle": "Land" },
{ "sTitle": "Uppdaterad" },
{ "sTitle": "Neutrala Posts", "sClass": "center" },
{ "sTitle": "Post / Client", "sClass": "center" },
{ "sTitle": "Ratio", "sClass": "center" },
{ "sTitle": "Total Posts", "sClass": "center" }
]
} );
/* Init DataTables */
var oTable = $('#example').dataTable();
/* Apply the jEditable handlers to the table */
$('td', oTable.fnGetNodes()).editable( 'editable_ajax.php', {
"callback": function( sValue, y ) {
var aPos = oTable.fnGetPosition( this );
oTable.fnUpdate( sValue, aPos[0], aPos[1] );
},
"submitdata": function ( value, settings ) {
return {
"row_id": this.parentNode.getAttribute('id'),
"column": oTable.fnGetPosition( this )[2]
};
},
"height": "14px"
} );
});
</script>
实时编辑是一种工作方式,当我点击一个单元格时,我会看到一个输入框。但是保存部分不起作用。。我不知道如何相应地更新我的数据库
有什么想法吗?在php文件中保存到数据库。您在那里做了什么?在IE或Chrome中安装firebug或激活调试控制台,查看事务的工作方式,或在ajax调用中添加错误,或将错误发送到console.log