Php SQL联接替换不需要的列

我创建了一个

JOIN

查询，以便能够从

users

表中访问

username

列，其中

t.user\u id=u.id

不幸的是，创建此查询后出现了一个问题。现在，当我尝试使用触发器表中的

id

时，我的变量正在从

users

表中拾取

id

有人知道我怎么解决这个问题吗

try {
    $con = getConfig('pdo');
    $con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $sql_triggers = "
        SELECT
            t.*,
            u.id,
            u.username
        FROM
            triggers AS t
        LEFT JOIN
            users AS u ON t.user_id = u.id
    ";
    $triggers_stmt = $con->prepare($sql_triggers);
    $triggers_stmt->execute();
    $triggers_rows = $triggers_stmt->fetchAll(PDO::FETCH_ASSOC);
    $triggers_arr = array();
    foreach ($triggers_rows as $triggers_row) {
        $trigger_id = $triggers_row['id'];
        $trigger_title = $triggers_row['trigger_name'];
        $trigger_description = $triggers_row['description'];
        $trigger_setting = $triggers_row['setting'];
        $trigger_user = $triggers_row['user_id'];
        $trigger_username = $triggers_row['username'];

触发器=t

CREATE TABLE `triggers` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `trigger_name` varchar(70) COLLATE utf8_unicode_ci NOT NULL,
 `setting` varchar(20) COLLATE utf8_unicode_ci NOT NULL,
 `description` text COLLATE utf8_unicode_ci NOT NULL,
 `user_id` int(11) NOT NULL,
 `placement` varchar(10) COLLATE utf8_unicode_ci NOT NULL,
 `date_changed` datetime NOT NULL,
 PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=3 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci

用户=u

CREATE TABLE `users` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `firstname` varchar(55) COLLATE utf8_unicode_ci NOT NULL,
 `lastname` varchar(55) COLLATE utf8_unicode_ci NOT NULL,
 `email` varchar(55) COLLATE utf8_unicode_ci NOT NULL,
 `username` varchar(70) COLLATE utf8_unicode_ci NOT NULL,
 `password` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
 `salt` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
 `joined` datetime NOT NULL,
 `last_login` datetime NOT NULL,
 `group` int(11) NOT NULL,
 PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=24 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_c

---

我能够修改SQL以获得我想要的结果。用户

id

列与触发器

id

列冲突。正如奈杰伦指出的，将

u.id，

更改为

u.id作为uid，

解决了这个问题

SELECT
    t.*,
    u.id AS uid,
    u.username
FROM
    triggers AS t
LEFT JOIN
    users AS u ON t.user_id = u.id
";

---

保罗？我发表了一条评论，我想你已经回复我了。因为两个表都有相同的字段名，所以你需要区分它们。您可以在sql语句中使用u.id作为UID，然后在后续操作中引用UID。@FunkFortyner我没有看到您的评论，抱歉。我删除了它，因为有人关闭了它。@jeff我会在这里这样做吗<代码>t.*，u.id，@Paul请发布您的答案/解决方案。奈杰尔重新开门。