如何用php上传目标文件夹中的文件？

我是新的PHP和学习它！ 我已经在本地主机名“submitpaper”上创建了一个简单的数据库 然后我创建了一个表名“upload\u file”，其中有两个字段file1和file2，它们都是VARCHAR 255 我在将文件保存到目标文件夹“testupload”时遇到问题

请检查和审查我的PHP脚本和HTML

PHP脚本

HTML文件代码

---

您试图错误地访问$\u FILES['file']['name']中的文件名。您必须使用类似$_FILES['nameoffile']['name']，其中nameoffile是您为文件输入字段指定的文件名。例如

$_FILES['file1']['name']

代码：

---

以下代码可能对您有用

$target = "Admin/upload/";
$target = $target . basename( $_FILES['uploaded_file']['name']); 
$pic=($_FILES['uploaded_file']['name']); 
//Writes the photo to the server 
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target)) 
{ 
    //Tells you if its all ok 
    //echo "The file ". basename( $_FILES['uploaded_file']['name']). " has been uploaded, and your information has been added to the directory"; 
} 
else 
{ 
    //Gives and error if its not 
    //echo "Sorry, there was a problem uploading your file."; 
} 

---

在此之前，您必须具有文件上载路径文件夹的读写权限。

目标文件夹是否已创建？如果不是，你需要先创建它，可以手动创建，也可以通过php脚本创建。你会遇到什么错误？我已经创建了php文件所在的目标文件夹！单击“提交”按钮后不显示仅显示PHP脚本时出错如果显示PHP脚本，则很可能您没有在服务器上运行该脚本。要运行php脚本，需要服务器安装wamp（如果是windows），lamp（如果是linux）。

$_FILES['file1']['name']

$target = "testupload/";
$target = $target . basename( $_FILES['file1']['name']);
if(move_uploaded_file($_FILES['file1']['tmp_name'], $target)) 
{
}

$target = "Admin/upload/";
$target = $target . basename( $_FILES['uploaded_file']['name']); 
$pic=($_FILES['uploaded_file']['name']); 
//Writes the photo to the server 
if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target)) 
{ 
    //Tells you if its all ok 
    //echo "The file ". basename( $_FILES['uploaded_file']['name']). " has been uploaded, and your information has been added to the directory"; 
} 
else 
{ 
    //Gives and error if its not 
    //echo "Sorry, there was a problem uploading your file."; 
}