Php 将秒转换为天、小时、分钟和秒
我想将一个变量Php 将秒转换为天、小时、分钟和秒,php,date,Php,Date,我想将一个变量$uptime转换为天、小时、分钟和秒，即秒 例如： $uptime=1640467； 结果应该是： 18天23小时41分钟 此函数重写为包含天。我还更改了变量名，使代码更容易理解 /** * Convert number of seconds into hours, minutes and seconds * and return an array containing those values * * @param integer $inputSeconds
$uptime$uptime=1640467；
18天23小时41分钟
/**
* Convert number of seconds into hours, minutes and seconds
* and return an array containing those values
*
* @param integer $inputSeconds Number of seconds to parse
* @return array
*/
function secondsToTime($inputSeconds) {
$secondsInAMinute = 60;
$secondsInAnHour = 60 * $secondsInAMinute;
$secondsInADay = 24 * $secondsInAnHour;
// extract days
$days = floor($inputSeconds / $secondsInADay);
// extract hours
$hourSeconds = $inputSeconds % $secondsInADay;
$hours = floor($hourSeconds / $secondsInAnHour);
// extract minutes
$minuteSeconds = $hourSeconds % $secondsInAnHour;
$minutes = floor($minuteSeconds / $secondsInAMinute);
// extract the remaining seconds
$remainingSeconds = $minuteSeconds % $secondsInAMinute;
$seconds = ceil($remainingSeconds);
// return the final array
$obj = array(
'd' => (int) $days,
'h' => (int) $hours,
'm' => (int) $minutes,
's' => (int) $seconds,
);
return $obj;
}
来源：CodeAid（）-这里是一个简单的8行PHP函数，它将秒数转换为人类可读的字符串，包括大量秒数的月数： 这可以通过类来实现 功能：
function secondsToTime（$seconds）{
$dtF=new\DateTime（“@0”）；
$dtT=new\DateTime（@$seconds）；
返回$dtF->diff（$dtT）->格式（“%a天、%h小时、%i分钟和%s秒”）；
}
echo secondsToTime（1640467）；
#18天23小时41分7秒
虽然这是一个很老的问题，但人们可能会发现这些问题很有用（不是写得太快）：
结果将是19 23:41:07。当它仅比正常的一天多出一秒钟时，它会将“天”值增加一天。这就是为什么它显示19。您可以根据需要分解结果并修复此问题。这是我过去使用的一个函数，用于从与您的问题相关的另一个日期中减去日期，我的原则是获得产品过期前还剩多少天、小时、分和秒：
$expirationDate = strtotime("2015-01-12 20:08:23");
$toDay = strtotime(date('Y-m-d H:i:s'));
$difference = abs($toDay - $expirationDate);
$days = floor($difference / 86400);
$hours = floor(($difference - $days * 86400) / 3600);
$minutes = floor(($difference - $days * 86400 - $hours * 3600) / 60);
$seconds = floor($difference - $days * 86400 - $hours * 3600 - $minutes * 60);
echo "{$days} days {$hours} hours {$minutes} minutes {$seconds} seconds";
这里有一些代码，我想用来获取两个日期之间的持续时间。它接受两个日期，并给你一个很好的句子结构的答复 这是找到的代码的稍微修改版本
的扩展版本，具有整数验证功能，解决1s问题，并在数年或数月内提供额外支持，其代价是减少对计算机解析的友好程度，使其更人性化：
<?php
function secondsToHumanReadable(/*int*/ $seconds)/*: string*/ {
//if you dont need php5 support, just remove the is_int check and make the input argument type int.
if(!\is_int($seconds)){
throw new \InvalidArgumentException('Argument 1 passed to secondsToHumanReadable() must be of the type int, '.\gettype($seconds).' given');
}
$dtF = new \DateTime ( '@0' );
$dtT = new \DateTime ( "@$seconds" );
$ret = '';
if ($seconds === 0) {
// special case
return '0 seconds';
}
$diff = $dtF->diff ( $dtT );
foreach ( array (
'y' => 'year',
'm' => 'month',
'd' => 'day',
'h' => 'hour',
'i' => 'minute',
's' => 'second'
) as $time => $timename ) {
if ($diff->$time !== 0) {
$ret .= $diff->$time . ' ' . $timename;
if ($diff->$time !== 1 && $diff->$time !== -1 ) {
$ret .= 's';
}
$ret .= ' ';
}
}
return substr ( $ret, 0, - 1 );
}
一体式解决方案。不提供带零的单位。将只生成您指定的单位数（默认为3）。
相当长，也许不是很优雅。定义是可选的，但在大型项目中可能会派上用场
define('OneMonth', 2592000);
define('OneWeek', 604800);
define('OneDay', 86400);
define('OneHour', 3600);
define('OneMinute', 60);
function SecondsToTime($seconds, $num_units=3) {
$time_descr = array(
"months" => floor($seconds / OneMonth),
"weeks" => floor(($seconds%OneMonth) / OneWeek),
"days" => floor(($seconds%OneWeek) / OneDay),
"hours" => floor(($seconds%OneDay) / OneHour),
"mins" => floor(($seconds%OneHour) / OneMinute),
"secs" => floor($seconds%OneMinute),
);
$res = "";
$counter = 0;
foreach ($time_descr as $k => $v) {
if ($v) {
$res.=$v." ".$k;
$counter++;
if($counter>=$num_units)
break;
elseif($counter)
$res.=", ";
}
}
return $res;
}
可以随意否决投票，但一定要在代码中尝试。它可能正是您所需要的。最简单的方法是创建一个方法，该方法从DateTime:：diff返回相对时间的DateInterval，从当前时间$now开始，以$s为单位，然后您可以链接并格式化它。例如：-
public function toDateInterval($seconds) {
return date_create('@' . (($now = time()) + $seconds))->diff(date_create('@' . $now));
}
现在将方法调用链接到DateInterval:：format
echo $this->toDateInterval(1640467)->format('%a days %h hours %i minutes'));
结果:
18 days 23 hours 41 minutes
可以使用我写的Interval类。它也可以以相反的方式使用
composer require lubos/cakephp-interval
$Interval = new \Interval\Interval\Interval();
// output 2w 6h
echo $Interval->toHuman((2 * 5 * 8 + 6) * 3600);
// output 36000
echo $Interval->toSeconds('1d 2h');
此处的更多信息基于Julian Moreno的答案，但更改为以字符串（而非数组）形式给出响应，仅包括所需的时间间隔，不采用复数形式
这个答案与得票最高的答案之间的区别是：
对于259264
秒，此代码将给出
3天1分4秒
对于259264
秒，投票率最高的答案（格拉维奇）将给出
3天、0小时、1分钟和4秒
我希望这对某人有所帮助。简短、简单、可靠：
function secondsToDHMS($seconds) {
$s = (int)$seconds;
return sprintf('%d:%02d:%02d:%02d', $s/86400, $s/3600%24, $s/60%60, $s%60);
}
应排除0值并设置正确的单数/复数值的解决方案
use DateInterval;
use DateTime;
class TimeIntervalFormatter
{
public static function fromSeconds($seconds)
{
$seconds = (int)$seconds;
$dateTime = new DateTime();
$dateTime->sub(new DateInterval("PT{$seconds}S"));
$interval = (new DateTime())->diff($dateTime);
$pieces = explode(' ', $interval->format('%y %m %d %h %i %s'));
$intervals = ['year', 'month', 'day', 'hour', 'minute', 'second'];
$result = [];
foreach ($pieces as $i => $value) {
if (!$value) {
continue;
}
$periodName = $intervals[$i];
if ($value > 1) {
$periodName .= 's';
}
$result[] = "{$value} {$periodName}";
}
return implode(', ', $result);
}
}
与：
这里有一些很好的答案，但没有一个能满足我的需要。我在此基础上添加了一些我需要的额外功能
- 不要打印零。所以用“5分钟”代替“0小时5分钟”
- 正确处理复数形式，而不是默认为复数形式
- 将输出限制为设定的单位数；所以“2个月2天”而不是“2个月2天1小时45分钟”
您可以看到代码的运行版本
我使用的这个解决方案（回到学习PHP的时候）没有任何内部函数：
$days = (int)($uptime/86400); //1day = 86400seconds
$rdays = (uptime-($days*86400));
//seconds remaining after uptime was converted into days
$hours = (int)($rdays/3600);//1hour = 3600seconds,converting remaining seconds into hours
$rhours = ($rdays-($hours*3600));
//seconds remaining after $rdays was converted into hours
$minutes = (int)($rhours/60); // 1minute = 60seconds, converting remaining seconds into minutes
echo "$days:$hours:$minutes";
虽然这是一个老问题，但遇到这个问题的新学员可能会发现这个答案很有用
foreach ($email as $temp => $value) {
$dat = strtotime($value['subscription_expiration']); //$value come from mysql database
//$email is an array from mysqli_query()
$date = strtotime(date('Y-m-d'));
$_SESSION['expiry'] = (((($dat - $date)/60)/60)/24)." Days Left";
//you will get the difference from current date in days.
}
$value来自数据库。此代码位于Codeigniter中$会话用于存储用户订阅。这是强制性的。我在我的案例中使用了它，你可以使用你想要的任何东西。我不知道为什么这些答案中有一些长得可笑或复杂。这里有一个使用。有点像拉德斯伯格的答案。这将只显示所需的单位，负时间将有'ago'后缀
a=int(input("Enter your number by seconds "))
d=a//(24*3600) #Days
h=a//(60*60)%24 #hours
m=a//60%60 #minutes
s=a%60 #seconds
print("Days ",d,"hours ",h,"minutes ",m,"seconds ",s)
function calctime($seconds = 0) {
$datetime1 = date_create("@0");
$datetime2 = date_create("@$seconds");
$interval = date_diff($datetime1, $datetime2);
if ( $interval->y >= 1 ) $thetime[] = pluralize( $interval->y, 'year' );
if ( $interval->m >= 1 ) $thetime[] = pluralize( $interval->m, 'month' );
if ( $interval->d >= 1 ) $thetime[] = pluralize( $interval->d, 'day' );
if ( $interval->h >= 1 ) $thetime[] = pluralize( $interval->h, 'hour' );
if ( $interval->i >= 1 ) $thetime[] = pluralize( $interval->i, 'minute' );
if ( $interval->s >= 1 ) $thetime[] = pluralize( $interval->s, 'second' );
return isset($thetime) ? implode(' ', $thetime) . ($interval->invert ? ' ago' : '') : NULL;
}
function pluralize($count, $text) {
return $count . ($count == 1 ? " $text" : " ${text}s");
}
// Examples:
// -86400 = 1 day ago
// 12345 = 3 hours 25 minutes 45 seconds
// 987654321 = 31 years 3 months 18 days 4 hours 25 minutes 21 seconds
编辑：如果您想将上面的示例压缩为使用更少的变量/空间（以牺牲易读性为代价），这里有一个替代版本可以做同样的事情：
function calctime($seconds = 0) {
$interval = date_diff(date_create("@0"),date_create("@$seconds"));
foreach (array('y'=>'year','m'=>'month','d'=>'day','h'=>'hour','i'=>'minute','s'=>'second') as $format=>$desc) {
if ($interval->$format >= 1) $thetime[] = $interval->$format . ($interval->$format == 1 ? " $desc" : " {$desc}s");
}
return isset($thetime) ? implode(' ', $thetime) . ($interval->invert ? ' ago' : '') : NULL;
}
我正在编辑其中一个代码，以便在出现负值时很好地工作<代码>楼层（）
当值为负值时，函数未给出正确的计数。因此，我们需要在floor（）
函数中使用abs（）
函数。
$inputSeconds
变量可以是当前时间戳和所需日期之间的差值
/**
* Convert number of seconds into hours, minutes and seconds
* and return an array containing those values
*
* @param integer $inputSeconds Number of seconds to parse
* @return array
*/
function secondsToTime($inputSeconds) {
$secondsInAMinute = 60;
$secondsInAnHour = 60 * $secondsInAMinute;
$secondsInADay = 24 * $secondsInAnHour;
// extract days
$days = abs($inputSeconds / $secondsInADay);
$days = floor($days);
// extract hours
$hourSeconds = $inputSeconds % $secondsInADay;
$hours = abs($hourSeconds / $secondsInAnHour);
$hours = floor($hours);
// extract minutes
$minuteSeconds = $hourSeconds % $secondsInAnHour;
$minutes = abs($minuteSeconds / $secondsInAMinute);
$minutes = floor($minutes);
// extract the remaining seconds
$remainingSeconds = $minuteSeconds % $secondsInAMinute;
$seconds = abs($remainingSeconds);
$seconds = ceil($remainingSeconds);
// return the final array
$obj = array(
'd' => (int) $days,
'h' => (int) $hours,
'm' => (int) $minutes,
's' => (int) $seconds,
);
return $obj;
}
@Glavić答案的一个变体——这一个隐藏了前导零以获得更短的结果，并在正确的位置使用复数。它还消除了不必要的精度（例如，如果时差超过2小时，您可能不在乎有多少分钟或秒）
拉威尔例子
碳排放支持700多个地区
\Carbon\CarbonInterval:：seconds（1640467）->cascade（）->forHumans（）//2周4天23小时41分7秒
如果能加入Source，那就太好了。您是否愿意为这个函数添加几天？@knittledan，看起来不是这样：）@hsmoore.com我接着想了想$days=floor（$seconds/（60*60*24））；//提取小时数$除数，表示小时数=$秒%（60*60*24）$小时数=下限（$除以小时数/（60*60））；这在几天内都无法正常工作。您需要减去（$days*24）
use DateInterval;
use DateTime;
class TimeIntervalFormatter
{
public static function fromSeconds($seconds)
{
$seconds = (int)$seconds;
$dateTime = new DateTime();
$dateTime->sub(new DateInterval("PT{$seconds}S"));
$interval = (new DateTime())->diff($dateTime);
$pieces = explode(' ', $interval->format('%y %m %d %h %i %s'));
$intervals = ['year', 'month', 'day', 'hour', 'minute', 'second'];
$result = [];
foreach ($pieces as $i => $value) {
if (!$value) {
continue;
}
$periodName = $intervals[$i];
if ($value > 1) {
$periodName .= 's';
}
$result[] = "{$value} {$periodName}";
}
return implode(', ', $result);
}
}
function convert($seconds){
$string = "";
$days = intval(intval($seconds) / (3600*24));
$hours = (intval($seconds) / 3600) % 24;
$minutes = (intval($seconds) / 60) % 60;
$seconds = (intval($seconds)) % 60;
if($days> 0){
$string .= "$days days ";
}
if($hours > 0){
$string .= "$hours hours ";
}
if($minutes > 0){
$string .= "$minutes minutes ";
}
if ($seconds > 0){
$string .= "$seconds seconds";
}
return $string;
}
echo convert(3744000);
$d1 = new DateTime();
$d2 = new DateTime();
$d2->add(new DateInterval('PT'.$timespan.'S'));
$interval = $d2->diff($d1);
echo $interval->format('%a days, %h hours, %i minutes and %s seconds');
// Or
echo sprintf('%d days, %d hours, %d minutes and %d seconds',
$interval->days,
$interval->h,
$interval->i,
$interval->s
);
// $interval->y => years
// $interval->m => months
// $interval->d => days
// $interval->h => hours
// $interval->i => minutes
// $interval->s => seconds
// $interval->days => total number of days
function secondsToHumanReadable(int $seconds, int $requiredParts = null)
{
$from = new \DateTime('@0');
$to = new \DateTime("@$seconds");
$interval = $from->diff($to);
$str = '';
$parts = [
'y' => 'year',
'm' => 'month',
'd' => 'day',
'h' => 'hour',
'i' => 'minute',
's' => 'second',
];
$includedParts = 0;
foreach ($parts as $key => $text) {
if ($requiredParts && $includedParts >= $requiredParts) {
break;
}
$currentPart = $interval->{$key};
if (empty($currentPart)) {
continue;
}
if (!empty($str)) {
$str .= ', ';
}
$str .= sprintf('%d %s', $currentPart, $text);
if ($currentPart > 1) {
// handle plural
$str .= 's';
}
$includedParts++;
}
return $str;
}
$days = (int)($uptime/86400); //1day = 86400seconds
$rdays = (uptime-($days*86400));
//seconds remaining after uptime was converted into days
$hours = (int)($rdays/3600);//1hour = 3600seconds,converting remaining seconds into hours
$rhours = ($rdays-($hours*3600));
//seconds remaining after $rdays was converted into hours
$minutes = (int)($rhours/60); // 1minute = 60seconds, converting remaining seconds into minutes
echo "$days:$hours:$minutes";
foreach ($email as $temp => $value) {
$dat = strtotime($value['subscription_expiration']); //$value come from mysql database
//$email is an array from mysqli_query()
$date = strtotime(date('Y-m-d'));
$_SESSION['expiry'] = (((($dat - $date)/60)/60)/24)." Days Left";
//you will get the difference from current date in days.
}
a=int(input("Enter your number by seconds "))
d=a//(24*3600) #Days
h=a//(60*60)%24 #hours
m=a//60%60 #minutes
s=a%60 #seconds
print("Days ",d,"hours ",h,"minutes ",m,"seconds ",s)
function calctime($seconds = 0) {
$datetime1 = date_create("@0");
$datetime2 = date_create("@$seconds");
$interval = date_diff($datetime1, $datetime2);
if ( $interval->y >= 1 ) $thetime[] = pluralize( $interval->y, 'year' );
if ( $interval->m >= 1 ) $thetime[] = pluralize( $interval->m, 'month' );
if ( $interval->d >= 1 ) $thetime[] = pluralize( $interval->d, 'day' );
if ( $interval->h >= 1 ) $thetime[] = pluralize( $interval->h, 'hour' );
if ( $interval->i >= 1 ) $thetime[] = pluralize( $interval->i, 'minute' );
if ( $interval->s >= 1 ) $thetime[] = pluralize( $interval->s, 'second' );
return isset($thetime) ? implode(' ', $thetime) . ($interval->invert ? ' ago' : '') : NULL;
}
function pluralize($count, $text) {
return $count . ($count == 1 ? " $text" : " ${text}s");
}
// Examples:
// -86400 = 1 day ago
// 12345 = 3 hours 25 minutes 45 seconds
// 987654321 = 31 years 3 months 18 days 4 hours 25 minutes 21 seconds
function calctime($seconds = 0) {
$interval = date_diff(date_create("@0"),date_create("@$seconds"));
foreach (array('y'=>'year','m'=>'month','d'=>'day','h'=>'hour','i'=>'minute','s'=>'second') as $format=>$desc) {
if ($interval->$format >= 1) $thetime[] = $interval->$format . ($interval->$format == 1 ? " $desc" : " {$desc}s");
}
return isset($thetime) ? implode(' ', $thetime) . ($interval->invert ? ' ago' : '') : NULL;
}
/**
* Convert number of seconds into hours, minutes and seconds
* and return an array containing those values
*
* @param integer $inputSeconds Number of seconds to parse
* @return array
*/
function secondsToTime($inputSeconds) {
$secondsInAMinute = 60;
$secondsInAnHour = 60 * $secondsInAMinute;
$secondsInADay = 24 * $secondsInAnHour;
// extract days
$days = abs($inputSeconds / $secondsInADay);
$days = floor($days);
// extract hours
$hourSeconds = $inputSeconds % $secondsInADay;
$hours = abs($hourSeconds / $secondsInAnHour);
$hours = floor($hours);
// extract minutes
$minuteSeconds = $hourSeconds % $secondsInAnHour;
$minutes = abs($minuteSeconds / $secondsInAMinute);
$minutes = floor($minutes);
// extract the remaining seconds
$remainingSeconds = $minuteSeconds % $secondsInAMinute;
$seconds = abs($remainingSeconds);
$seconds = ceil($remainingSeconds);
// return the final array
$obj = array(
'd' => (int) $days,
'h' => (int) $hours,
'm' => (int) $minutes,
's' => (int) $seconds,
);
return $obj;
}
function secondsToTime($seconds)
{
$dtF = new \DateTime('@0');
$dtT = new \DateTime("@$seconds");
$dateInterval = $dtF->diff($dtT);
$days_t = 'day';
$hours_t = 'hour';
$minutes_t = 'minute';
$seconds_t = 'second';
if ((int)$dateInterval->d > 1) {
$days_t = 'days';
}
if ((int)$dateInterval->h > 1) {
$hours_t = 'hours';
}
if ((int)$dateInterval->i > 1) {
$minutes_t = 'minutes';
}
if ((int)$dateInterval->s > 1) {
$seconds_t = 'seconds';
}
if ((int)$dateInterval->d > 0) {
if ((int)$dateInterval->d > 1 || (int)$dateInterval->h === 0) {
return $dateInterval->format("%a $days_t");
} else {
return $dateInterval->format("%a $days_t, %h $hours_t");
}
} else if ((int)$dateInterval->h > 0) {
if ((int)$dateInterval->h > 1 || (int)$dateInterval->i === 0) {
return $dateInterval->format("%h $hours_t");
} else {
return $dateInterval->format("%h $hours_t, %i $minutes_t");
}
} else if ((int)$dateInterval->i > 0) {
if ((int)$dateInterval->i > 1 || (int)$dateInterval->s === 0) {
return $dateInterval->format("%i $minutes_t");
} else {
return $dateInterval->format("%i $minutes_t, %s $seconds_t");
}
} else {
return $dateInterval->format("%s $seconds_t");
}
}
php > echo secondsToTime(60);
1 minute
php > echo secondsToTime(61);
1 minute, 1 second
php > echo secondsToTime(120);
2 minutes
php > echo secondsToTime(121);
2 minutes
php > echo secondsToTime(2000);
33 minutes
php > echo secondsToTime(4000);
1 hour, 6 minutes
php > echo secondsToTime(4001);
1 hour, 6 minutes
php > echo secondsToTime(40001);
11 hours
php > echo secondsToTime(400000);
4 days