Php 将组合字符串拆分为数组

我在这里问了一个关于商店营业时间相似的日子的问题

现在，我需要一些帮助来做相反的事情：获取包含合并日期的字符串并将其拆分为单独的日期，然后将它们按日期顺序存储在数组中（Mon first，Sun last）

例如，以下是一组需要转换的字符串（格式完全相同）：

这两个字符串需要组合在一起并转换为此数组：

array[0] = "11am - 7:30pm"
array[1] = "11am - 7:30pm"
array[2] = "11am - 7:30pm"
array[3] = "11am - 7:30pm"
array[4] = "11am - 7:30pm"
array[5] = "11am - 6pm"
array[6] = ""             // Blank value if the day Sunday is not in the set of strings that needs conversion
// ideally it should be an associative array, ie. array['mon'] = "11am - 7:30pm"

顺便说一句，我正在使用Codeigniter PHP框架和jQuery

更新：

Array
(
[Mon] =>  9 pm - 1 am
[Tue] => 
[Wed] => 
[Thu] =>  7:30 pm - 2 am
[Fri] =>  7:30 pm - 2 am
[Sat] =>  7:30 pm - 2 am
[Sun] => 
)

我现在必须拆分这个包含逗号的文本字符串

Mon 9 pm - 1 am
Tue-Wed, Sun 7:30 pm - 1 am
Thu-Sat 7:30 pm - 2 am

结果数组：

Array
(
[Mon] =>  9 pm - 1 am
[Tue] => 
[Wed] => 
[Thu] =>  7:30 pm - 2 am
[Fri] =>  7:30 pm - 2 am
[Sat] =>  7:30 pm - 2 am
[Sun] => 
)

看来我得把星期二和星期三从太阳分开

Tue-Wed, Sun 7:30 pm - 1 am

到

---

@Khattam：这段时间：

Mon 9 pm - 1 am
Tue-Wed, Sun 7:30 pm - 1 am
Thu-Sat 7:30 pm - 2 am

给出：

Array
(
[Mon] => 9 pm - 1 am
[Tue] => 7:30 pm - 1 am
[Wed] => 7:30 pm - 1 am
[Thu] => 7:30 pm - 2 am
[Fri] => 7:30 pm - 2 am
[Sat] => 7:30 pm - 2 am
[Sun] => 
[
] => 
)

---

使用

RegExp

解析天数，然后对集合中的每一天使用相同的值迭代天数

var hrsCondensed = ["Mon-Fri 11 am - 7:30 pm", "Sat 11 am - 6 pm"];
var hrsExpanded = ["","","","","","",""];
var days = ["Mon","Tue","Wed","Thu","Fri","Sat","Sun"];
$.each(hrsCondensed, function()
{
    if (/([a-z]{3})-([a-z]{3}) (.+)/i.test(this))
    {
        var start = RegExp.$1;
        var end = RegExp.$2;
        var hrs = RegExp.$3;
        var i = $.inArray(start, days);
        hrsExpanded[i] = hrs;
        while(days[i] != end)
        {
            if (++i > 6) i = 0;
            hrsExpanded[i] = hrs;
        }
    }
    else
    {
        var day = this.substr(0, 3);
        var hrs = this.substr(4);
        var i = $.inArray(day, days);
        hrsExpanded[i] = hrs;
    }
});

---

实时工作示例：

使用正则表达式

示例（快速和肮脏）：

---

资料来源：，

这应该让您开始学习

var dates = ['Mon-Fri 11 am - 7:30 pm','Sat 11 am - 6 pm'];//for testing
    var regex = '(\\w{3})-?(\\w{3})?\\s+(.*)';
    var week = {'Mon':0, 'Tue':1, 'Wed':2, 'Thu':3, 'Fri':4, 'Sat':5, 'Sun':6};
    function foo(){
        var datum = [];
        re = new RegExp(regex);
        for(i in dates){
            match = re.exec(dates[i]);
            if(match != null){
                from = week[match[1]];
                to = match[2]? week[match[2]]: from;
                tim = match[3];

                for(i=from; i<=to; ++i){
                    datum[i] = tim;
                }
            }
        }

        alert(datum);
    }

var dates=[“周一至周五上午11点至下午7:30”，“周六上午11点至下午6点]//用于测试
var regex='（\\w{3}）-？（\\w{3}）\\s+（.*）；
变量week={'Mon'：0，'Tue'：1，'Wed'：2，'Thu'：3，'Fri'：4，'Sat'：5，'Sun'：6}；
函数foo（）{
var数据=[]；
re=新的RegExp（regex）；
（i）日期{
匹配=重新执行（日期[i]）；
如果（匹配！=null）{
from=周[匹配[1]]；
to=匹配[2]？周[匹配[2]：开始；
tim=匹配[3]；
对于（i=from；i，您还可以使用控制器操作，其代码类似于以下代码：

<?php
$days = array(    
    'Mon',
    'Tue',
    'Wed',
    'Thu',
    'Fri',
    'Sat',
    'Sun'
);
$combined = "Tue-Wed, Sun 7:30 pm - 1 am";
$combined = explode("\n",$combined);

foreach($combined as &$c){
    $commaPosition = strpos($c,', ');
    if($commaPosition!==false){
        array_push($combined,substr($c,$commaPosition+2));
        $spacePosition = strpos($c,' ',$commaPosition+2);
        $c = substr($c,0,$commaPosition).substr($c,$spacePosition);
    }
}

$splitArray = array();
foreach($days as $d){
    $splitArray[$d]='';
}
foreach($combined as $c){
    $daysRange = explode(' ',$c);
    $daysRange = $daysRange[0];
    if(strpos($daysRange,'-')===false){
        $splitArray[$daysRange] = substr($c,strlen($daysRange)+1);
    }
    else{
        $temp = explode('-',$daysRange);
        $dayStart = $temp[0];
        $dayStartIndex = array_search($dayStart,$days);
        $dayEnd = $temp[1];
        $dayEndIndex = array_search($dayEnd,$days);
        for($i=$dayStartIndex;$i<=$dayEndIndex;$i++){
            $splitArray[$days[$i]] = substr($c,strlen($daysRange)+1);
        }
    }
}

echo json_encode($splitArray);

你有一些代码吗？你试过什么吗？我有点困了，有大量的if/else语句考虑案例
周一周二、周一周三、周一周四、周一周五、周一周六、周一周日、周二周三、周二周四…
等思考用
-
拆分字符串然后解决问题。太好了！现在我有了一个strING如上面更新的问题所示，代码现在需要考虑逗号……我想TimeWe必须在<代码> $aysReals和“爆炸<代码>”、“<代码> >定界符和另外的<代码> ELSIF < /COD>条件>代码> ELSIF（STRPOS（$DaysRange'，'-'）= TRUE & & STRPOS（$aysAsLead，''，'））=真）
，然后我被卡住了：（@Nyxynyx刚刚添加了一个循环，将带有逗号的格式更改为旧格式。这应该可以工作。
Mon-Fri 11 am - 7:30 pm ==> 11 am,7:30 pm
Sat 11 am - 6 pm ==> 11 am,6 pm

var dates = ['Mon-Fri 11 am - 7:30 pm','Sat 11 am - 6 pm'];//for testing
    var regex = '(\\w{3})-?(\\w{3})?\\s+(.*)';
    var week = {'Mon':0, 'Tue':1, 'Wed':2, 'Thu':3, 'Fri':4, 'Sat':5, 'Sun':6};
    function foo(){
        var datum = [];
        re = new RegExp(regex);
        for(i in dates){
            match = re.exec(dates[i]);
            if(match != null){
                from = week[match[1]];
                to = match[2]? week[match[2]]: from;
                tim = match[3];

                for(i=from; i<=to; ++i){
                    datum[i] = tim;
                }
            }
        }

        alert(datum);
    }

<?php
$days = array(    
    'Mon',
    'Tue',
    'Wed',
    'Thu',
    'Fri',
    'Sat',
    'Sun'
);
$combined = "Tue-Wed, Sun 7:30 pm - 1 am";
$combined = explode("\n",$combined);

foreach($combined as &$c){
    $commaPosition = strpos($c,', ');
    if($commaPosition!==false){
        array_push($combined,substr($c,$commaPosition+2));
        $spacePosition = strpos($c,' ',$commaPosition+2);
        $c = substr($c,0,$commaPosition).substr($c,$spacePosition);
    }
}

$splitArray = array();
foreach($days as $d){
    $splitArray[$d]='';
}
foreach($combined as $c){
    $daysRange = explode(' ',$c);
    $daysRange = $daysRange[0];
    if(strpos($daysRange,'-')===false){
        $splitArray[$daysRange] = substr($c,strlen($daysRange)+1);
    }
    else{
        $temp = explode('-',$daysRange);
        $dayStart = $temp[0];
        $dayStartIndex = array_search($dayStart,$days);
        $dayEnd = $temp[1];
        $dayEndIndex = array_search($dayEnd,$days);
        for($i=$dayStartIndex;$i<=$dayEndIndex;$i++){
            $splitArray[$days[$i]] = substr($c,strlen($daysRange)+1);
        }
    }
}

echo json_encode($splitArray);