Php 三个不同的表合一视图laravel 5.2

嗨，我想用laravel 5.2在一个视图中显示三个不同的表格。但我似乎有问题

my HomeController.php

namespace App\Http\Controllers;

use Illuminate\Http\Request;
use DB;
use App\Http\Requests;
use App\Http\Controllers\Controller;

class HomeController extends Controller
{
    public function index()
    {
        $about = DB::select('select * from about');
        $teams = DB::select('select * from teams');
        $services = DB::select('select * from services');

        return view('master', ['about' => $about], ['teams' => $teams], ['services' => $services]);
    }
}

我认为：

@foreach ($about as $abt)
      <h4>{{$abt->title}}</h4>
      <span class="semi-separator center-block"></span>
      <p>{{$abt->description}}</p>
@endforeach

@foreach ($teams as $team)
     <div class="creative-symbol cs-creative">
        <img src="assets/images/new/{{$team->icon}}" alt="">
        <span class="semi-separator center-block"></span>
        <h4><b>{{$team->title}}</b></h4>
        <p>{{$team->description}}</p>
     </div>
@endforeach

@foreach（$abt左右）
{{$abt->title}
{{$abt->description}

@endforeach
@foreach（$teams作为$team）
图标}}“alt=”“>
{{$team->title}
{{$team->description}

@endforeach

我无法显示第三个，即$services。请帮助我。

---

当我添加第三个时，它将显示一个错误

请更改：

        return view('master', ['about' => $about], ['teams' => $teams], ['services' => $services]);

为此：

        return view('master', ['about' => $about, 'teams' => $teams, 'services' => $services]);

---

在Laravel 5.1中，我在

/vendor/Laravel/framework/src/illumb/Foundation/helpers.php

中找到了以下代码：

if (! function_exists('view')) {
    /**
     * Get the evaluated view contents for the given view.
     *
     * @param  string  $view
     * @param  array   $data
     * @param  array   $mergeData
     * @return \Illuminate\View\View|\Illuminate\Contracts\View\Factory
     */
    function view($view = null, $data = [], $mergeData = [])
    {
        $factory = app(ViewFactory::class);

        if (func_num_args() === 0) {
            return $factory;
        }

        return $factory->make($view, $data, $mergeData);
    }
}

这是您试图调用的函数。请注意有多少个参数（共3个）。您试图传入4个参数。我认为您试图执行的操作如下：

return view('master', [
    'about' => $about, 
    'teams' => $teams, 
    'services' => $services
]);

---

这正在调用同一个函数，但只传递了两个参数。

什么意思？你不能显示第三个参数？你只发布了两个参数的代码。当我添加第三个参数时，它将显示一个错误@ceejayoz它显示了什么错误？没问题！我喜欢laravel！快乐编码：-）