Php for循环中不需要的数组组合
我花了两天时间试图理解为什么我会得到如此不合逻辑的结果。让我举例说明。我基于这个简单的数组创建发票Php for循环中不需要的数组组合,php,arrays,for-loop,foreach,cycle,Php,Arrays,For Loop,Foreach,Cycle,我花了两天时间试图理解为什么我会得到如此不合逻辑的结果。让我举例说明。我基于这个简单的数组创建发票 Array ( [0] => Array ( [userid] => 208 [number_of_services] => 3 [username1] => sara [income1] => 10
Array
(
[0] => Array
(
[userid] => 208
[number_of_services] => 3
[username1] => sara
[income1] => 10
[username2] => mark
[income2] => 18
[username3] => joe
[income3] => 12
)
[1] => Array
(
[userid] => 4
[number_of_services] => 1
[username1] => bruce
[income1] => 5
)
[2] => Array
(
[userid] => 303
[number_of_services] => 1
[username1] => michael
[income1] => 7
)
)
使用此数组,我希望为具有以下ID的客户创建3张发票:208、4、303。我可以用一个简单的foreach
foreach($myarray AS $key => $value)
{
// create my invoice
}
现在您可以看到ID为208的客户端有多个用户名。我将它们存储为[username1]、[username2]、[username3]等等
[0] => Array
(
[userid] => 208
[number_of_services] => 3
[username1] => sara
[income1] => 10
[username2] => mark
[income2] => 18
[username3] => joe
[income3] => 12
)
我想在发票中将每个用户名显示为新行(项目),因此我执行以下操作:
foreach($myarray AS $key => $value)
{
for($n=1; $n<=$value["number_of_services"]; $n++)
{
$invoice["itemdescription$n"] = "Username: ".$value["username$n"]."";
$invoice["itemamount$n"] = $value["income$n"];
$invoice["itemtaxed$n"] = 1;
}
}
foreach($myarray作为$key=>$value)
{
对于($n=1;$n 5欧元)
客户303的1张发票和1个项目(迈克尔->7欧元)
客户208的1张发票,3项(sara->10,mark->18,joe->12)
但我总是得到:
- 客户4的1张发票,3项(布鲁斯->5欧元,马克->18,乔->12)
- 客户303的1张发票和3个项目(迈克尔->7欧元,马克->18,乔->12)
- 客户208的1张发票,3项(sara->10,mark->18,joe->12)
我不明白为什么脚本不断将客户机208的[username2]、[income2]和[username3]、[income3]合并到客户机4和303!我在每一步都调试了脚本,问题似乎出现在for()循环中
有什么想法吗?foreach($key=>myarray$value)
foreach($myarray AS $key => $value)
{
for($n=1; $n<=$value["number_of_services"]; $n++)
{
$invoice[] = array(
"itemdescription" => "Username: " . $value . "username" . $n,
"itemamount" . $n = $value . "income" . $n,
"itemtaxed" . $n = 1
);
}
}
{
对于($n=1;$n“用户名:”.$value.“用户名”.$n,
“项目金额”。$n=$value。“收入”。$n,
“项目税”。$n=1
);
}
}
尝试此操作。此代码按预期工作。显示显示输出的其他代码。