Php 复杂sql查询-计数+；具有+；分组方式-如何修复查询

我正在寻找有关sql中一个相当复杂的查询的帮助

查询听起来应该像：（下面的第一个查询） 我正在寻找的产品类型是：床，我想显示分配给他们的所有选项-分组，并计算其中有多少。（如下图所示）

查询的第二部分：（下面的第二个查询） 当用户单击复选框时，我只想显示和统计已选中选项的产品，并统计这些产品的数量。（这就是问题所在）

第一个问题：

SELECT COUNT(DISTINCT id_product) as productMatched, COUNT(id_product) as haveProducts, product_to_features.id_feature_value, product_to_features.id_feature, feature_value_langs.name,feature_value_langs.id_feature_value, products.active 
FROM product_to_features 
LEFT JOIN feature_value_langs 
   ON product_to_features.id_feature_value = feature_value_langs.id_feature_value 
LEFT JOIN products 
   ON product_to_features.id_product = products.id 
WHERE price_retail >= 655.00 
   AND price_retail <= 6455.00 
   AND height >= 0.0 AND height <= 120.0 
   AND width >= 0.0 AND width <= 262.0 
   AND depth >= 0.0 AND depth <= 276.0 
   AND product_to_features.id_feature_value IN (15981,15982,15983,16011,16012,16013,16019)  //its shows ids of bed sizes
   AND products.active = 1 
GROUP BY product_to_features.id_feature_value

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请看您使用的是MySQL还是MS SQL Server？不要标记未涉及的产品。抱歉，我单击了错误的建议-当然是MySQL。现在也是了解别名和限定列名的重要性的好时机-例如，从my_table x中的

，其中x.price_retail>=655和x.price_retail=0和x.height
SELECT COUNT(DISTINCT product_to_features.id_feature_value) as productMatched, COUNT(product_to_features.id_product) as haveProducts, product_to_features.id_feature_value, product_to_features.id_feature, id_product as ProductId, feature_value_langs.name, products.active 
FROM product_to_features 
LEFT JOIN feature_value_langs 
   ON product_to_features.id_feature_value = feature_value_langs.id_feature_value 
LEFT JOIN products 
   ON product_to_features.id_product = products.id 
WHERE price_retail >= 655 AND price_retail <= 6455 
   AND height >= 0 AND height <= 120 
   AND width >= 0 AND width <= 262 
   AND depth >= 0 AND depth <= 276 
   AND (product_to_features.id_feature_value IN (15981,15982,15983,16011,16012,16013,16019)  // (its first checkbox group where non is checked - so i send all values )
   OR product_to_features.id_feature_value IN ( 1096)  // 1096 - its checked option from second checkbox group)
   OR product_to_features.id_feature_value = 1483 )   // 1483 - is BED TYPE (must be)
  AND products.active = 1 
GROUP BY product_to_features.id_product having productMatched>2 
ORDER BY product_to_features.id_feature

DESCRIBE product_to_features

id  int(11) NO  PRI     auto_increment  
id_feature  int(10) unsigned    NO  MUL         
id_product  int(10) unsigned    NO  MUL         
id_feature_value    int(10) unsigned    NO  MUL     


desc `feature_value_langs`

id  int(11) NO  PRI     auto_increment  
id_feature_value    int(10) unsigned    NO  MUL         
id_lang int(10) unsigned    NO  MUL         
name    varchar(255)    YES MUL