PHP-将数组值组合为两个唯一的对

PHP-将数组值组合为两个唯一的对,php,arrays,combinations,permutation,Php,Arrays,Combinations,Permutation,我正在尝试转换以下数组 Array ( [304] => Array ( [0] => 102 [1] => 177 [2] => 132 [3] => 223 ) [302] => Array (

我正在尝试转换以下数组

    Array
    (
        [304] => Array
            (
                [0] => 102
                [1] => 177
                [2] => 132
                [3] => 223
            )
        [302] => Array
            (
                [0] => 132
                [1] => 96
            )
    )
具体如下:

    Array
    (
        [0] => Array
            (
                ["source"] => 102
                ["target"] => 177
            )
        [1] => Array
            (
                ["source"] => 102
                ["target"] => 132
            )
        [2] => Array
            (
                ["source"] => 102
                ["target"] => 223
            )
        [3] => Array
            (
                ["source"] => 177
                ["target"] => 132
            )
        [4] => Array
            (
                ["source"] => 177
                ["target"] => 223
            )
        [4] => Array
            (
                ["source"] => 132
                ["target"] => 223
            )
        // only two values, so just one pair
        [5] => Array
            (
                ["source"] => 132
                ["target"] => 96
            )
    )
所以我得到了所有可能的配对,没有任何重复

我尝试了很多东西,比如带if语句的循环中的循环,但我不知道从哪里开始。。。 例如:

    $new_links = array();
     foreach($arr as $arr_new){
      foreach($arr_new as $key => $value){
        if($key == 0){
          $source=$value;
        }else{
          $new_links[$key]["source"]=$source;
          $new_links[$key]["target"]=$value;
        }
      }
     }
其中$arr是给定的数组

所以我的问题是:实现这一目标最有效的方法是什么

提前谢谢

---编辑---

多亏了

我只需要编辑一点语法就可以让它运行,但是逻辑工作起来很有魅力

我的最终结果是:

    // the given array is $arr
    $result = array();

    foreach ($arr as $group)
    {
        $lastIdx = count($group) - 1;
        $startIdx = 1;

        foreach ($group as $member)
        {
            for ($pos = $startIdx; $pos <= $lastIdx; $pos++)
            {
                $result[] = array(
                    'source' => $member,
                    'target' => $group[$pos]
                );
            }

            $startIdx++;
        }
    }

我试了很多东西。向我们展示。阅读相关主题。可能重复的尝试使用多维array@mickmackusa不知道该解释什么。。所以添加了评论。谢谢。为解决方案添加解释可以做很多伟大的事情。1.提高未来回答的文化预期标准。2.在教育/授权OP和未来研究人员方面做得很好。3.使使用现有页面作为资源关闭新的重复问题更有帮助。4.提高您赢得更多选票的可能性。5.使StackOverflow成为所有人的最佳资源。。。再次感谢您抽出时间。请永远带着教育的意图回答。
<?php

$input = [[102,177,132,223],[132,96]];
$result = [];

// for each group of elements in input array
foreach ($input as $group)
{
    // set the first target element of the group to be
    // second element
    $nextTargetIdx = 1;

    // determine last target index beforehand
    // so that value gets computed only once per group
    $lastTargetIdx = count($group) - 1;

    // then, take each element of that group as source
    foreach ($group as $source)
    {
        // and 
        for // every next element
        (
            $targetIdx = $nextTargetIdx;
            $targetIdx <= $lastTargetIdx;
            $targetIdx++
        )
        {
            // add new result entry
            $result[] = [
                // with current source
                'source' => $source,
                // and target
                'target' => $group[$targetIdx]
            ];
        }

        // then, when all targets for current source are found
        // increase next target index so that it follows next source element
        $nextTargetIdx++;
    }
}

var_dump($result);