Php 需要在表中插入“；医生；（id为自动递增）。不知道查询出了什么问题。我得到错误-“；网页不可用；。帮助解决它

在
$country=$\u POST[country']中缺少
”

$country=$_POST['country'];
$sql = "INSERT INTO $table (firstname,lastname,speciality,hospital,city,state,country)VALUES ('$firstname','$lastname','$speciality','$hospital','$city','$state','$country')";
$result =mysql_query($sql);
if ($result) {

更改此
$country=$\u POST[country']至
$country=$\u POST['country']

$country=$_POST['country'];
$sql = "INSERT INTO $table (firstname,lastname,speciality,hospital,city,state,country)VALUES ('$firstname','$lastname','$speciality','$hospital','$city','$state','$country')";
$result =mysql_query($sql);
if ($result) {

更新代码：

改变这个

mysql_connect( $host, $username, $password ) or  die(" could not connect to database..." .mysql_error ());
mysql_select_db($database) or die ("Could not connect to database..." .mysql_error ());

到

语法

mysql_选择_数据库（连接，数据库名）

所以，connection和dbname是必填字段。将连接值传递给mysql\u select\u db

[注意：
mysql函数
被折旧。使用
PDO
或
mysqli.*函数
]

<?php

$host = 'localhost';
$username = 'uai';
$password = '';
$database = 'Pharma';
$table = 'doctors';

$con = mysql_connect( $host, $username, $password ) or  die(" could not connect to database..." .mysql_error ());
$db = mysql_select_db($database,$con) or die ("Could not connect to database..." .mysql_error ());

$firstname =$_POST['firstname'];
$lastname =$_POST['lastname'];
$speciality =$_POST['speciality'];
$hospital=$_POST['hospital'];
$city=$_POST['city'];
$state=$_POST['state'];
$country=$_POST['country'];
$sql = "INSERT INTO $table (firstname,lastname,speciality,hospital,city,state,country)VALUES ('$firstname','$lastname','$speciality','$hospital','$city','$state','$country')";
$result =mysql_query($sql);
if ($result) {
echo "New record created successfully";
}
else {
echo "Insertion Error: ";
}
?>
<?php
mysql_close();
?>

在
$country=$\u POST[country']中缺少
”
你在那里遇到了什么错误？请编辑带有完整错误的问题@ganeshvasanthwhat是此页面的页面名称。仔细检查
标记action属性@ganeshvasanthform action=doctors.php，这是doctors.php页面。因此，请同时发布您的
。然后，只有我们能找到。还有一件事。doctors.php位于同一文件夹中@ganeshvasanthI改变了一些密码。请看一看@ganeshvasanth
$con = mysql_connect( $host, $username, $password ) or  die(" could not connect to database..." .mysql_error ());
$db = mysql_select_db($database,$con) or die ("Could not connect to database..." .mysql_error ());

connection =>   Required. Specifies the MySQL connection to use
dbname =>       Required. Specifies the default database to be used

<?php

$host = 'localhost';
$username = 'uai';
$password = '';
$database = 'Pharma';
$table = 'doctors';

$con = mysql_connect( $host, $username, $password ) or  die(" could not connect to database..." .mysql_error ());
$db = mysql_select_db($database,$con) or die ("Could not connect to database..." .mysql_error ());

$firstname =$_POST['firstname'];
$lastname =$_POST['lastname'];
$speciality =$_POST['speciality'];
$hospital=$_POST['hospital'];
$city=$_POST['city'];
$state=$_POST['state'];
$country=$_POST['country'];
$sql = "INSERT INTO $table (firstname,lastname,speciality,hospital,city,state,country)VALUES ('$firstname','$lastname','$speciality','$hospital','$city','$state','$country')";
$result =mysql_query($sql);
if ($result) {
echo "New record created successfully";
}
else {
echo "Insertion Error: ";
}
?>
<?php
mysql_close();
?>

<?php
$host = 'localhost';
$username = 'uai';
$password = '';
$database = 'Pharma';
$table = 'doctors';

$con = mysqli_connect($host, $username, $password,$database) or die(" could not connect to database..." .mysqli_connect_error());

$firstname =$_POST['firstname'];
$lastname =$_POST['lastname'];
$speciality =$_POST['speciality'];
$hospital=$_POST['hospital'];
$city=$_POST['city'];
$state=$_POST['state'];
$country=$_POST['country'];

$result = mysqli_query($con,"INSERT INTO $table (firstname,lastname,speciality,hospital,city,state,country)VALUES ('$firstname','$lastname','$speciality','$hospital','$city','$state','$country')");

if ($result) {
    echo "New record created successfully";
}
else {
    echo "Insertion Error: ";
}

mysqli_close($con);
?>