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Php 如何向sql server添加数据_Php_Html_Mysql_Sql - Fatal编程技术网

Php 如何向sql server添加数据

Php 如何向sql server添加数据,php,html,mysql,sql,Php,Html,Mysql,Sql,嗨,伙计们,我两个月前就开始创建一个网站了,就在我创建网站的一周前,我就触底了。我的问题是,我无法让它将数据添加到我的SQL数据库中,该数据库是我使用000webhost.com包提供的SQL数据库和phpmyadmin创建的 下面是我的PHP代码,底部是HTML: <?php $con=mysqli_connect("mysql11.000webhost.com","xxxxxxxx","xxxxxxxxx","xxxxxxxx"); if (mysqli_connect_errn

嗨,伙计们,我两个月前就开始创建一个网站了,就在我创建网站的一周前,我就触底了。我的问题是,我无法让它将数据添加到我的SQL数据库中,该数据库是我使用000webhost.com包提供的SQL数据库和phpmyadmin创建的

下面是我的PHP代码,底部是HTML:

 <?php
 $con=mysqli_connect("mysql11.000webhost.com","xxxxxxxx","xxxxxxxxx","xxxxxxxx");
 if (mysqli_connect_errno()) {
 echo "Failed to connect to MySQL: " . mysqli_connect_error();
 }
 $mysqli_query("INSERT INTO userreg (email,password,name)
 VALUES ('Peterbaob@gmail.com', 'gigtit',bob_name)");
 echo"adding is done";

 ?>
 <!DOCTYPE html>
 <html lang="en">
 <head>
 <title>Friend It sign up</title>

 <link rel="stylesheet" type="text/css" href="  css/bootstrap.css">
 <link rel="stylesheet" type="text/css" href="  css/bootstrap.min.css">
 <link rel="stylesheet" type="text/css" href="css/bootstrap-theme.css">
 <link rel="stylesheet" type="text/css" href="  css/bootstrap-theme.min.css">
 <link rel="stylesheet" type="text/css" href="  css/index.css">
  </head>

  <body>
  <ul class="nav nav-pills"> 
  <li><a href="index.html">Home</a></li>
  <li><a href="About.html">About</a></li>
  <label class="web-name">Friend It</label>
  </ul>

  <div class="page-header">
  <h1>Sign up</h1>
  </div>

  <div class="container">    
  <div id="loginbox" style="margin-top:50px;" class="mainbox col-md-6 col-md-offset-col-sm-8 col-sm-offset-2">                    
  <div class="panel panel-primary" >
  <div class="panel-heading">
  <div class="panel-title">Sign up</div>                      
  </div>  
  <div style="padding-top:30px" class="panel-body" >

  <from action="connect.php" method="post">                              
  <div style="margin-bottom: 25px" class="input-group">
  <span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span>
  <input  id="login-username" name="user" type="text" class="form-control" name="username" value="" placeholder="email">                                      
  </div>

  <div style="margin-bottom: 25px" class="input-group">
  <span class="input-group-addon"><i class="glyphicon glyphicon-pencil"></i></span>
  <input id="login-username" type="text" name="fullname" class="form-control" name="username" value="" placeholder="Full Name">      
  </form>                                     
  </div>

  <div style="margin-bottom: 25px" class="input-group">
  <span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span>
  <input id="login-password" name="pass" type="password" class="form-control" name="password" placeholder="Password">
  </div>

   <div style="margin-bottom: 25px" class="input-group">
   <span class="input-group-addon"><i class="glyphicon glyphicon-repeat"></i></span>
   <input id="login-password" type="password" class="form-control" name="passwordre" placeholder="Re-type Password">
   </div>                              
   <div style="margin-top:10px"  class="form-group">                                   
   <div style="margin-left:140px" class="col-sm-12 controls">
   <a  id="btn-signup" href="connect.php" class="btn btn-primary" type="submit">Sign up</a>                                      
   </div>
   </div>
   </form>
   </div>
   </div>                                 
   </div>                     
   </div>  
   </div>


   <script src="js/bootstrap.min.js"></script>
   </body>
   </html>

您也可以通过转到

来查看该网站。尝试此查询,我认为唯一的问题是名称列的值应该用单引号括起来,但缺少单引号

 $mysqli_query("INSERT INTO userreg (email,password,name)
 VALUES ('Peterbaob@gmail.com', 'gigtit','bob_name')");

希望获得以下帮助:

问题出在您的查询中,请尝试以下方法:

$mysqli_query("INSERT INTO userreg (email,password,name) 
VALUES ('Peterbaob@gmail.com', 'gigtit','bob_name')");

对于您的第二个错误编辑:您将其作为关于错误括号的注释发布 你可以查一下 或者发布导致错误的那一行。

函数是mysqli\u query而不是$mysqli\u query,我不知道为什么其他人没有捕捉到这一点

mysqli_query("INSERT INTO userreg (email,password,name) 
              VALUES ('Peterbaob@gmail.com', 'gigtit', 'bob_name')");
因为它是程序样式,所以可以将连接作为第一个参数传递:

mysqli_query($con, "INSERT INTO userreg (email,password,name) 
                    VALUES ('Peterbaob@gmail.com', 'gigtit', 'bob_name')");

请检查您是否提供了由000webhost生成的相同密码…否则请说明哪里有错误?抱歉,仅此而已mistake@user223784你又一次没有接受我的回答!我尝试了这段代码,但现在我收到了一种新的错误致命错误:函数名必须是第12行/home/a8206989/public_html/connect.php中的字符串。您可以在friendit.net16.net/connect.php上看到此错误