PHP分页不会更改页面上的值
我使用了php分页教程:。正如它所说的,这很容易,我没想到会有任何问题。然而,我遇到了一个。现在我知道为了获得最好的结果,您应该看到我的源代码,所以我将提供它。问题是,如果成员是正确的,它可以很好地查询,并且只在页面上显示某些数据,并将其限制为每页仅显示几个数据。。。但是,当我尝试更改以在下一页上看到更多注释时,它不会更改值PHP分页不会更改页面上的值,php,pagination,Php,Pagination,我使用了php分页教程:。正如它所说的,这很容易,我没想到会有任何问题。然而,我遇到了一个。现在我知道为了获得最好的结果,您应该看到我的源代码,所以我将提供它。问题是,如果成员是正确的,它可以很好地查询,并且只在页面上显示某些数据,并将其限制为每页仅显示几个数据。。。但是,当我尝试更改以在下一页上看到更多注释时,它不会更改值 <?php /* $dbLink = mysql_connect("localhost", "sco0100_james", "cr
<?php
/* $dbLink = mysql_connect("localhost", "sco0100_james", "creeper");
mysql_query("SET character_set_results=utf8", $dbLink);
mb_language('uni');
mb_internal_encoding('UTF-8');
*/
include('config.php'); // include your code to connect to DB.
$tbl_name="commenttable"; //your table name
$adjacents = 3;
/*
First get total number of rows in data table.
If you have a WHERE clause in your query, make sure you mirror it here.
*/
$query = "SELECT COUNT(*) as num FROM $tbl_name";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];
/* Setup vars for query. */
$targetpage = "profile.php?id=$id"; //the name of this file
$limit = 3; //how many items to show per page
$page = $_GET['page'];
if($page)
$start = ($page - 1) * $limit;
//first item to display on this page
else
$start = 0; //if no page var is given, set start to 0
/* Get data. */
$sql = "SELECT id, name, comment, member1, member2 FROM $tbl_name WHERE member2='".$id."' ORDER BY id ASC LIMIT $start, $limit";
$result = mysql_query($sql);
/* Setup page vars for display. */
if ($page == 0)
$page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit);
//lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case
we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous button
if ($page > 1)
$pagination.= "<a href=\"$targetpage?page=$prev\">previous</a>";
else
$pagination.= "<span class=\"disabled\">� previous</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2))
//not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2))
//enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href=\"$targetpage?page=$next\">next</a>";
else
$pagination.= "<span class=\"disabled\">next</span>";
$pagination.= "</div>\n";
}
while($row = mysql_fetch_array($result))
{
$cname= $row['name'];
$comment= $row['comment'];
echo $cname . '<br/>' . '<br/>' . $comment . '<br/>' . '<br/>' . '<hr size="1"/>';
}
?>
<?=$pagination?>
您的SQL查询应该包含一个TOP和一个LIMIT值,以便您选择所需的范围(页面)。类似于此:
$items_per_page = 10;
$query = "SELECT TOP $items_per_page * FROM table LIMIT ". $items_per_page * $REQUEST['page'];
是,$targetpage
不正确:
$targetpage = "profile.php?id=$id";
将生成类似于profile.php?id=42的内容。然后在URL中使用该字符串:
<a href=\"$targetpage?page=$counter etc..." />
$limit是“我的代码”中的每页项目数变量。这显示在$sql查询中。但我现在要改变一下,看看会发生什么,谢谢。这会在调用它的代码中产生一个错误。错误为:警告:mysql\u fetch\u array():提供的参数不是有效的mysql结果资源。这是我将其更改为:$sql=“SELECT TOP$limit*FROM$tbl_name WHERE member2=”“$id.”“ORDER BY id ASC limit”$限额*$REQUEST[“页面”];阿里加托。这已经奏效了。^嗯。。。就我现在看来,它已经奏效了。如果我以后发现它做错了什么,我会发回的
<a href="profile.php?id=42?page=XXX" />
<a href=\"$targetpage&page=$counter etc..." />
^--- &, not ?