Php 我对MySQL中的输出有一个问题
这是密码Php 我对MySQL中的输出有一个问题,php,mysql,Php,Mysql,这是密码 $connect = new mysqli($servername, $username, $password, $database); if ($connect->connect_error) { die("Unable to Connect : " . connect_error); } $sql = "CREATE TABLE student( student_id INT PRIMARY KEY, name VAR
$connect = new mysqli($servername, $username, $password, $database);
if ($connect->connect_error) {
die("Unable to Connect : " . connect_error);
}
$sql = "CREATE TABLE student(
student_id INT PRIMARY KEY,
name VARCHAR(50),
age INT,
gender VARCHAR(20)
);";
if ($connect->query($sql) === true) {
echo "New Tables has been Created <br><br>";
}
else {
echo "There is an Error : " . $connect->error . "<br><br>";
}
echo "Connected Successfully!";
$connect -> close();
我刚刚创建了一个表,我想问的是,当我要插入数据时,输出会像插入的新数据一样打印出来!但在不删除echo的情况下,创建了新表;这是可能的吗?如果需要{}的话,是不是需要else?这是一个非常基本的问题,但仍然:
...
if ($connect->query($sql) === true) {
echo "New Tables has been Created <br><be>";
// put your insert code here
}
...
只需在结束前的某个地方对插入代码进行编码。这是一个非常奇怪的问题,一个学生的年龄会给所有回答的人带来麻烦!你们都帮了大忙
...
if ($connect->query($sql) === true) {
echo "New Tables has been Created <br><be>";
// put your insert code here
}
...