Php 表中每列的频率列表_Php_Mysql

Php 表中每列的频率列表

php mysql

Php 表中每列的频率列表,php,mysql,Php,Mysql,我有一张这样的桌子： r01 r02 r03 r04 1 2 X X 1 2 X 1 X 1 2 1 X 2 2 2 1 2 1 X 1 1 1 2 1 X 1 1 1 2 X 1 2 2 X 2 我想为每一列（而不是每一行）获得一个频率数组列表，类似于array\u count\u values（）。像 r01: 1 => 6, X => 2, 2 => 1 r02:

我有一张这样的桌子：

r01 r02 r03 r04
1   2   X   X
1   2   X   1
X   1   2   1
X   2   2   2
1   2   1   X
1   1   1   2
1   X   1   1
1   2   X   1
2   2   X   2

我想为每一列（而不是每一行）获得一个频率数组列表，类似于

array\u count\u values（）

。像

r01: 1 => 6, X => 2, 2 => 1
r02: 1 => 2, X => 1, 2 => 6
r03: 1 => 3, X => 4, 2 => 2
r04: 1 => 4, X => 2, 2 => 3

有可能回答一个或几个mysql问题吗？我还没有想出一个好主意。我唯一的解决方案是将所有数据都放到PHP中，然后创建一个数据数组，只需为每行的相应计数器添加一个数据数组

我可以有100->20000行。因此，我希望有一个mysql解决方案，它比PHP解决方案具有更好的扩展性

--编辑

我正在显示一个简化的表结构，但我想我需要显示完整的表

CREATE TABLE IF NOT EXISTS `tips_rows` (
  `row_id` int(11) NOT NULL,
  `r01` enum('1','X','2') NOT NULL,
  `r02` enum('1','X','2') NOT NULL,
  `r03` enum('1','X','2') NOT NULL,
  `r04` enum('1','X','2') NOT NULL,
  `r05` enum('1','X','2') NOT NULL,
  `r06` enum('1','X','2') NOT NULL,
  `r07` enum('1','X','2') NOT NULL,
  `r08` enum('1','X','2') NOT NULL,
  `r09` enum('1','X','2') NOT NULL,
  `r10` enum('1','X','2') NOT NULL,
  `r11` enum('1','X','2') NOT NULL,
  `r12` enum('1','X','2') NOT NULL,
  `r13` enum('1','X','2') NOT NULL,
  PRIMARY KEY (`row_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

和tips_行包含所有值的组合。（160万行）我有一个链接表连接用户到tips_行，''tips_行''users'

因此，这个链接表将为许多用户保存一个数据集，每个用户的行id为100-10000

我在谷歌搜索的基础上找到了一个解决方案。也许不是最纯粹的查询，但它可以工作并且速度很快

 SELECT
    SUM(CASE WHEN r01 = '1' THEN 1 ELSE 0 END) AS r11,
    SUM(CASE WHEN r01 = 'X' THEN 1 ELSE 0 END) AS r1X,
    SUM(CASE WHEN r01 = '2' THEN 1 ELSE 0 END) AS r12,
    SUM(CASE WHEN r02 = '1' THEN 1 ELSE 0 END) AS r21,
    SUM(CASE WHEN r02 = 'X' THEN 1 ELSE 0 END) AS r2X,
    SUM(CASE WHEN r02 = '2' THEN 1 ELSE 0 END) AS r22,
    SUM(CASE WHEN r03 = '1' THEN 1 ELSE 0 END) AS r31,
    SUM(CASE WHEN r03 = 'X' THEN 1 ELSE 0 END) AS r3X,
    SUM(CASE WHEN r03 = '2' THEN 1 ELSE 0 END) AS r32,
    SUM(CASE WHEN r04 = '1' THEN 1 ELSE 0 END) AS r41,
    SUM(CASE WHEN r04 = 'X' THEN 1 ELSE 0 END) AS r4X,
    SUM(CASE WHEN r04 = '2' THEN 1 ELSE 0 END) AS r42,
    SUM(CASE WHEN r05 = '1' THEN 1 ELSE 0 END) AS r51,
    SUM(CASE WHEN r05 = 'X' THEN 1 ELSE 0 END) AS r5X,
    SUM(CASE WHEN r05 = '2' THEN 1 ELSE 0 END) AS r52,
    SUM(CASE WHEN r06 = '1' THEN 1 ELSE 0 END) AS r61,
    SUM(CASE WHEN r06 = 'X' THEN 1 ELSE 0 END) AS r6X,
    SUM(CASE WHEN r06 = '2' THEN 1 ELSE 0 END) AS r62,
    SUM(CASE WHEN r07 = '1' THEN 1 ELSE 0 END) AS r71,
    SUM(CASE WHEN r07 = 'X' THEN 1 ELSE 0 END) AS r7X,
    SUM(CASE WHEN r07 = '2' THEN 1 ELSE 0 END) AS r72,
    SUM(CASE WHEN r08 = '1' THEN 1 ELSE 0 END) AS r81,
    SUM(CASE WHEN r08 = 'X' THEN 1 ELSE 0 END) AS r8X,
    SUM(CASE WHEN r08 = '2' THEN 1 ELSE 0 END) AS r82,
    SUM(CASE WHEN r09 = '1' THEN 1 ELSE 0 END) AS r91,
    SUM(CASE WHEN r09 = 'X' THEN 1 ELSE 0 END) AS r9X,
    SUM(CASE WHEN r09 = '2' THEN 1 ELSE 0 END) AS r92,
    SUM(CASE WHEN r10 = '1' THEN 1 ELSE 0 END) AS r101,
    SUM(CASE WHEN r10 = 'X' THEN 1 ELSE 0 END) AS r10X,
    SUM(CASE WHEN r10 = '2' THEN 1 ELSE 0 END) AS r102,
    SUM(CASE WHEN r11 = '1' THEN 1 ELSE 0 END) AS r111,
    SUM(CASE WHEN r11 = 'X' THEN 1 ELSE 0 END) AS r11X,
    SUM(CASE WHEN r11 = '2' THEN 1 ELSE 0 END) AS r112,
    SUM(CASE WHEN r12 = '1' THEN 1 ELSE 0 END) AS r121,
    SUM(CASE WHEN r12 = 'X' THEN 1 ELSE 0 END) AS r12X,
    SUM(CASE WHEN r12 = '2' THEN 1 ELSE 0 END) AS r122,
    SUM(CASE WHEN r13 = '1' THEN 1 ELSE 0 END) AS r131,
    SUM(CASE WHEN r13 = 'X' THEN 1 ELSE 0 END) AS r13X,
    SUM(CASE WHEN r13 = '2' THEN 1 ELSE 0 END) AS r132
    FROM `tips_rows` AS r
    INNER JOIN tips_rows_users USING (row_id)
    WHERE user__id='{userid}'

这将给我一个结果行作为

r11 r1X r12 r21 r2X r22 r31 r3X r32 r41 r4X r42 r51 r5X r52 r61 r6X r62 r71 r7X r72 r81 r8X r82 r91 r9X r92 r101 r10X r102 r111 r11X r112 r121 r12X r122 r131 r13X r132
40  34  26  48  30  22  69  14  17  70  16  14  15  17  68  28  31  41  80  20  0   49  29  22  38  30  32  69   16   15   29   28   43   19   31   50   13   25   62

我可以在我的php模板文件中使用它。

试试这个：

Select 'R01', r01, count(1) from myTable group by r01
UNION 
Select 'R02', r02, count(1) from myTable group by r02 
UNION
Select 'R03', r03, count(1) from myTable group by r03 
UNION
Select 'R04', r04, count(1) from myTable group by r04

假设每列只有4列和3个可能的值，如果您确实希望结果显示为“每值一列”：

制作：

+------+----+----+---+
| ROW  | 1  | 2  | X |
+------+----+----+---+
| R01  | 6  | 1  | 2 |
| R02  | 2  | 6  | 1 |
| R03  | 3  | 2  | 4 |
| R04  | 4  | 3  | 2 |
+------+----+----+---+

看

如果可以接受对结果表进行数据透视，则以下查询将执行得更好：

导致：

+----+------+------+------+-----+
|    | R01  | R02  | R03  | R04 |
+----+------+------+------+-----+
| 1  |   6  |   2  |   3  |   4 |
| 2  |   1  |   6  |   2  |   3 |
| X  |   2  |   1  |   4  |   2 |
+----+------+------+------+-----+

感谢所有不同的解决方案。我现在已经对我的数据做了一些测试。我已经查询了10000行。这是我的发现

解决方案1：

Select 'R01', r01, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r01
UNION 
Select 'R02', r02, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r02 
UNION
Select 'R03', r03, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r03 
UNION
Select 'R04', r04, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r04 
UNION
Select 'R05', r05, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r05 
UNION
Select 'R06', r06, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r06 
UNION
Select 'R07', r07, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r07 
UNION
Select 'R08', r08, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r08 
UNION
Select 'R09', r09, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r09 
UNION
Select 'R10', r10, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r10 
UNION
Select 'R11', r11, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r11 
UNION
Select 'R12', r12, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r12 
UNION
Select 'R13', r13, count(1) FROM `tips_rows` AS r INNER JOIN tips_rows_users USING (row_id) WHERE user_id='27' group by r13

每次查询大约需要0.1365s

解决方案2：

SELECT n,
       SUM(IF(r01 = n, 1, 0)) AS 'r01',
       SUM(IF(r02 = n, 1, 0)) AS 'r02',
       SUM(IF(r03 = n, 1, 0)) AS 'r03',
       SUM(IF(r04 = n, 1, 0)) AS 'r04',
       SUM(IF(r05 = n, 1, 0)) AS 'r05',
       SUM(IF(r06 = n, 1, 0)) AS 'r06',
       SUM(IF(r07 = n, 1, 0)) AS 'r07',
       SUM(IF(r08 = n, 1, 0)) AS 'r08',
       SUM(IF(r09 = n, 1, 0)) AS 'r09',
       SUM(IF(r10 = n, 1, 0)) AS 'r10',
       SUM(IF(r11 = n, 1, 0)) AS 'r11',
       SUM(IF(r12 = n, 1, 0)) AS 'r12',
       SUM(IF(r13 = n, 1, 0)) AS 'r13'       
FROM `tips_rows` AS r
INNER JOIN tips_rows_users USING (row_id)
JOIN (SELECT '1' AS n UNION SELECT '2' UNION SELECT 'X') S
WHERE user_id='27'
GROUP BY n;

第一次查询大约需要0.0997秒。可以缓存在mysql查询缓存中，因此第二次需要约0.0002秒

解决方案3：

SELECT
    SUM(CASE WHEN r01 = '1' THEN 1 ELSE 0 END) AS r11,
    SUM(CASE WHEN r01 = 'X' THEN 1 ELSE 0 END) AS r1X,
    SUM(CASE WHEN r01 = '2' THEN 1 ELSE 0 END) AS r12,
    SUM(CASE WHEN r02 = '1' THEN 1 ELSE 0 END) AS r21,
    SUM(CASE WHEN r02 = 'X' THEN 1 ELSE 0 END) AS r2X,
    SUM(CASE WHEN r02 = '2' THEN 1 ELSE 0 END) AS r22,
    SUM(CASE WHEN r03 = '1' THEN 1 ELSE 0 END) AS r31,
    SUM(CASE WHEN r03 = 'X' THEN 1 ELSE 0 END) AS r3X,
    SUM(CASE WHEN r03 = '2' THEN 1 ELSE 0 END) AS r32,
    SUM(CASE WHEN r04 = '1' THEN 1 ELSE 0 END) AS r41,
    SUM(CASE WHEN r04 = 'X' THEN 1 ELSE 0 END) AS r4X,
    SUM(CASE WHEN r04 = '2' THEN 1 ELSE 0 END) AS r42,
    SUM(CASE WHEN r05 = '1' THEN 1 ELSE 0 END) AS r51,
    SUM(CASE WHEN r05 = 'X' THEN 1 ELSE 0 END) AS r5X,
    SUM(CASE WHEN r05 = '2' THEN 1 ELSE 0 END) AS r52,
    SUM(CASE WHEN r06 = '1' THEN 1 ELSE 0 END) AS r61,
    SUM(CASE WHEN r06 = 'X' THEN 1 ELSE 0 END) AS r6X,
    SUM(CASE WHEN r06 = '2' THEN 1 ELSE 0 END) AS r62,
    SUM(CASE WHEN r07 = '1' THEN 1 ELSE 0 END) AS r71,
    SUM(CASE WHEN r07 = 'X' THEN 1 ELSE 0 END) AS r7X,
    SUM(CASE WHEN r07 = '2' THEN 1 ELSE 0 END) AS r72,
    SUM(CASE WHEN r08 = '1' THEN 1 ELSE 0 END) AS r81,
    SUM(CASE WHEN r08 = 'X' THEN 1 ELSE 0 END) AS r8X,
    SUM(CASE WHEN r08 = '2' THEN 1 ELSE 0 END) AS r82,
    SUM(CASE WHEN r09 = '1' THEN 1 ELSE 0 END) AS r91,
    SUM(CASE WHEN r09 = 'X' THEN 1 ELSE 0 END) AS r9X,
    SUM(CASE WHEN r09 = '2' THEN 1 ELSE 0 END) AS r92,
    SUM(CASE WHEN r10 = '1' THEN 1 ELSE 0 END) AS r101,
    SUM(CASE WHEN r10 = 'X' THEN 1 ELSE 0 END) AS r10X,
    SUM(CASE WHEN r10 = '2' THEN 1 ELSE 0 END) AS r102,
    SUM(CASE WHEN r11 = '1' THEN 1 ELSE 0 END) AS r111,
    SUM(CASE WHEN r11 = 'X' THEN 1 ELSE 0 END) AS r11X,
    SUM(CASE WHEN r11 = '2' THEN 1 ELSE 0 END) AS r112,
    SUM(CASE WHEN r12 = '1' THEN 1 ELSE 0 END) AS r121,
    SUM(CASE WHEN r12 = 'X' THEN 1 ELSE 0 END) AS r12X,
    SUM(CASE WHEN r12 = '2' THEN 1 ELSE 0 END) AS r122,
    SUM(CASE WHEN r13 = '1' THEN 1 ELSE 0 END) AS r131,
    SUM(CASE WHEN r13 = 'X' THEN 1 ELSE 0 END) AS r13X,
    SUM(CASE WHEN r13 = '2' THEN 1 ELSE 0 END) AS r132
    FROM `tips_rows` AS r
    INNER JOIN tips_rows_users USING (row_id)
    WHERE user_id='27'

第一次和第二次需要约0.0587秒。在那之后0.0002s作为后面的问题

我将使用解决方案3。因为它有最好的最坏的情况下的时间。但是奇怪的是，在缓存之前需要两个查询。

每个列可能有多少个不同的值的可能副本？@ SelvayLeRoux不相关的评论？“SulkFipe非严肃的：是否只有3个可能值PAR列‘1’、‘2’和‘x’？或更多？由于预期结果似乎是每个值显示一列，这对重复问题有影响。那里的解决方案不起作用，因为我有几个专栏。使用下面的联合解决方案可能是可行的。不起作用。我越来越累了#1222-使用的SELECT语句具有不同的列数。这只会出现，如果r01、r02、r03、r04的数据类型不同，请检查并confirm@Kristoffer：1另外，请将您正在使用的确切查询与发现问题的创建表一起粘贴。您在R03上输入了一个拼写错误，'位于的错误一侧，但这迫使我多次查询160万个大表。希望将其包含在一个查询中。它可能无法工作。因为这将迫使我多次查询包含160万行的mysql表。@Kristofer这是您想要“透视”表时要支付的价格。如果你想要“一行中的所有内容”，你自己的解决方案可能是最好的。如果可以接受旋转90°的“表格”报告，您可以稍微简化查询（参见上面的编辑）。

SELECT n,
       SUM(IF(r01 = n, 1, 0)) AS 'r01',
       SUM(IF(r02 = n, 1, 0)) AS 'r02',
       SUM(IF(r03 = n, 1, 0)) AS 'r03',
       SUM(IF(r04 = n, 1, 0)) AS 'r04',
       SUM(IF(r05 = n, 1, 0)) AS 'r05',
       SUM(IF(r06 = n, 1, 0)) AS 'r06',
       SUM(IF(r07 = n, 1, 0)) AS 'r07',
       SUM(IF(r08 = n, 1, 0)) AS 'r08',
       SUM(IF(r09 = n, 1, 0)) AS 'r09',
       SUM(IF(r10 = n, 1, 0)) AS 'r10',
       SUM(IF(r11 = n, 1, 0)) AS 'r11',
       SUM(IF(r12 = n, 1, 0)) AS 'r12',
       SUM(IF(r13 = n, 1, 0)) AS 'r13'       
FROM `tips_rows` AS r
INNER JOIN tips_rows_users USING (row_id)
JOIN (SELECT '1' AS n UNION SELECT '2' UNION SELECT 'X') S
WHERE user_id='27'
GROUP BY n;

SELECT
    SUM(CASE WHEN r01 = '1' THEN 1 ELSE 0 END) AS r11,
    SUM(CASE WHEN r01 = 'X' THEN 1 ELSE 0 END) AS r1X,
    SUM(CASE WHEN r01 = '2' THEN 1 ELSE 0 END) AS r12,
    SUM(CASE WHEN r02 = '1' THEN 1 ELSE 0 END) AS r21,
    SUM(CASE WHEN r02 = 'X' THEN 1 ELSE 0 END) AS r2X,
    SUM(CASE WHEN r02 = '2' THEN 1 ELSE 0 END) AS r22,
    SUM(CASE WHEN r03 = '1' THEN 1 ELSE 0 END) AS r31,
    SUM(CASE WHEN r03 = 'X' THEN 1 ELSE 0 END) AS r3X,
    SUM(CASE WHEN r03 = '2' THEN 1 ELSE 0 END) AS r32,
    SUM(CASE WHEN r04 = '1' THEN 1 ELSE 0 END) AS r41,
    SUM(CASE WHEN r04 = 'X' THEN 1 ELSE 0 END) AS r4X,
    SUM(CASE WHEN r04 = '2' THEN 1 ELSE 0 END) AS r42,
    SUM(CASE WHEN r05 = '1' THEN 1 ELSE 0 END) AS r51,
    SUM(CASE WHEN r05 = 'X' THEN 1 ELSE 0 END) AS r5X,
    SUM(CASE WHEN r05 = '2' THEN 1 ELSE 0 END) AS r52,
    SUM(CASE WHEN r06 = '1' THEN 1 ELSE 0 END) AS r61,
    SUM(CASE WHEN r06 = 'X' THEN 1 ELSE 0 END) AS r6X,
    SUM(CASE WHEN r06 = '2' THEN 1 ELSE 0 END) AS r62,
    SUM(CASE WHEN r07 = '1' THEN 1 ELSE 0 END) AS r71,
    SUM(CASE WHEN r07 = 'X' THEN 1 ELSE 0 END) AS r7X,
    SUM(CASE WHEN r07 = '2' THEN 1 ELSE 0 END) AS r72,
    SUM(CASE WHEN r08 = '1' THEN 1 ELSE 0 END) AS r81,
    SUM(CASE WHEN r08 = 'X' THEN 1 ELSE 0 END) AS r8X,
    SUM(CASE WHEN r08 = '2' THEN 1 ELSE 0 END) AS r82,
    SUM(CASE WHEN r09 = '1' THEN 1 ELSE 0 END) AS r91,
    SUM(CASE WHEN r09 = 'X' THEN 1 ELSE 0 END) AS r9X,
    SUM(CASE WHEN r09 = '2' THEN 1 ELSE 0 END) AS r92,
    SUM(CASE WHEN r10 = '1' THEN 1 ELSE 0 END) AS r101,
    SUM(CASE WHEN r10 = 'X' THEN 1 ELSE 0 END) AS r10X,
    SUM(CASE WHEN r10 = '2' THEN 1 ELSE 0 END) AS r102,
    SUM(CASE WHEN r11 = '1' THEN 1 ELSE 0 END) AS r111,
    SUM(CASE WHEN r11 = 'X' THEN 1 ELSE 0 END) AS r11X,
    SUM(CASE WHEN r11 = '2' THEN 1 ELSE 0 END) AS r112,
    SUM(CASE WHEN r12 = '1' THEN 1 ELSE 0 END) AS r121,
    SUM(CASE WHEN r12 = 'X' THEN 1 ELSE 0 END) AS r12X,
    SUM(CASE WHEN r12 = '2' THEN 1 ELSE 0 END) AS r122,
    SUM(CASE WHEN r13 = '1' THEN 1 ELSE 0 END) AS r131,
    SUM(CASE WHEN r13 = 'X' THEN 1 ELSE 0 END) AS r13X,
    SUM(CASE WHEN r13 = '2' THEN 1 ELSE 0 END) AS r132
    FROM `tips_rows` AS r
    INNER JOIN tips_rows_users USING (row_id)
    WHERE user_id='27'