如何使此php代码成为html中的下拉菜单？
这就是我的php代码的样子：如何使此php代码成为html中的下拉菜单？,php,html,sql-server-2008,Php,Html,Sql Server 2008,这就是我的php代码的样子： <html> Client list:<br><br> <?php $serverName = "NEPTUNE\SQLEXPRESS"; $connectionOptions = array("Database"=>"tcd", "UID"=>"tcd", "PWD"=>"technician"); $conn = sqlsrv_connect( $serverName, $connectionOpt
<html>
Client list:<br><br>
<?php
$serverName = "NEPTUNE\SQLEXPRESS";
$connectionOptions = array("Database"=>"tcd", "UID"=>"tcd", "PWD"=>"technician");
$conn = sqlsrv_connect( $serverName, $connectionOptions);
if( $conn === false ) {
die( FormatErrors( sqlsrv_errors() ) );
}
$sql = "SELECT client_name FROM client";
$stmt = sqlsrv_query( $conn, $sql );
if( $stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC) ) {
echo $row[0]."<br />";
}
sqlsrv_free_stmt( $stmt);
?>
</html>
客户列表：
这将返回一个成功的查询。如何使用HTML中的select标记从下拉菜单中选择一个查询选项？如果抓取没有问题，只需像通常那样将其与HTML select+选项标记组合即可
<html>
Client list:<br><br>
<?php
$serverName = "NEPTUNE\SQLEXPRESS";
$connectionOptions = array("Database"=>"tcd", "UID"=>"tcd", "PWD"=>"technician");
$conn = sqlsrv_connect( $serverName, $connectionOptions);
if( $conn === false ) {
die( FormatErrors( sqlsrv_errors() ) );
}
$sql = "SELECT client_name FROM client";
$stmt = sqlsrv_query( $conn, $sql );
if( $stmt === false) {
die( print_r( sqlsrv_errors(), true) );
}
?>
<select name="whatever">
<?php while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_NUMERIC) ): ?>
<option value="<?php echo $row[0]; ?>"><?php echo $row[0]; ?></option>
<?php endwhile; ?>
</select>
<?php sqlsrv_free_stmt( $stmt); ?>
</html>
客户列表：
改变回声。。到html中进行选择？也不确定你需要什么