Php 如何从Ramsey\uuid\Codec\StringCodec提取uuid?
到目前为止,从以下几行Php 如何从Ramsey\uuid\Codec\StringCodec提取uuid?,php,symfony4,Php,Symfony4,到目前为止,从以下几行 $records = $this->entityManager->getRepository(Translation::class)->findBy([], ['id' => 'DESC'], 1, 0); $uuid = $records[0]->getId(); 我能听到下面的句子 Ramsey\Uuid\Uuid {#131 #codec: Ramsey\Uuid\Codec\StringCodec {#86 -build
$records = $this->entityManager->getRepository(Translation::class)->findBy([], ['id' => 'DESC'], 1, 0);
$uuid = $records[0]->getId();
我能听到下面的句子
Ramsey\Uuid\Uuid {#131
#codec: Ramsey\Uuid\Codec\StringCodec {#86
-builder: Ramsey\Uuid\Builder\DefaultUuidBuilder {#383
-converter: Ramsey\Uuid\Converter\Number\DegradedNumberConverter {#390}
}
}
#fields: array:6 [
"time_low" => "1483fc71"
"time_mid" => "66e9"
"time_hi_and_version" => "4e21"
"clock_seq_hi_and_reserved" => "b9"
"clock_seq_low" => "50"
"node" => "c6e9e6405428"
]
#converter: Ramsey\Uuid\Converter\Number\DegradedNumberConverter {#390}
uuid: "1483fc71-66e9"
}
如何提取
uuid
?该类实现PHP的\uuu-toString
方法,因此您可以将对象强制转换为字符串:
$uuid = (string) $records[0]->getId();
使用
Ramsey\Uuid\Uuid
可以通过几种方式将Uuid提取为字符串。基本方法是Ramsey\Uuid\Uuid::toString()
,因此对于类似这样的代码示例:
$uuid = $records[0]->getId()->toString();
对于命名约定,存在一些包装器方法,所有这些方法都调用Ramsey\Uuid\Uuid::toString()
:
当然,您可以将整个对象强制转换为字符串,就像前面提到的@iainn一样
Ramsey\Uuid\Uuid::serialize()
Ramsey\Uuid\Uuid::jsonSerialize()