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PHP,从链接请求并回显json数组_Php_Html_Arrays_Json_Post - Fatal编程技术网

PHP,从链接请求并回显json数组

PHP,从链接请求并回显json数组,php,html,arrays,json,post,Php,Html,Arrays,Json,Post,我有这个代码,但它似乎不工作。在文本字段中输入IP并点击按钮后,它将返回加载到php代码的页面,但不会加载php代码结果或任何经过它的代码 <?php if(isset($_POST['resolve'])){ $api = "https://iphub.p.mashape.com/api.php?ip="; $endbit = "&showtype=4"; if(strlen($_POST['name'])==0){ echo "fill

我有这个代码,但它似乎不工作。在文本字段中输入IP并点击按钮后,它将返回加载到php代码的页面,但不会加载php代码结果或任何经过它的代码

<?php
if(isset($_POST['resolve'])){
    $api = "https://iphub.p.mashape.com/api.php?ip=";

    $endbit = "&showtype=4";
    if(strlen($_POST['name'])==0){
        echo "fill in all fields!";
    } else {
        // assuming $_POST['resolve'] has an IP

      //  $response = file_get_contents($api.$_POST['name'].$endbit); 

      $response = Unirest\Request::get($api.$_POST['name'].$endbit,
array(
"X-Mashape-Key" => "U3sk6nAZzBmshyiHEUZHigxLGp1ZTZnKjsnkd8LWULJmRRp",
"Accept" => "application/json"
  )
);



        ?>

        <div align="center">

        <?php 
        if($response['proxy'] == '0') {
            echo 'No';
        }
        elseif($response['proxy'] == '1') {
            echo 'Yes';
        }
        else {
            echo 'Error.';
        }
        ?>

        </div>

        <?php
     }
}
?>

我正在使用的API要求我具有头/X-Mashape-Key。

是否有错误报告;在…上加载Unirest类可能是一个致命错误?我如何将错误报告全部;on?这段代码在你的页面的最顶端吗?实际上这并不重要,因为你说它达到了这一点并且失败了。收到此错误后:致命错误:在第254行的/var/www/html/proxy.php中找不到类“Unirest\Request”