Php 如何在laravel中获得每个Id的总和并将其分离

这是我在控制器中的查询

我的查询结果。。。我想得到单独的

项目\u代码的总数

我也试过这个，但它只能得到所有的总和

我的查询结果

我想要达到的结果

"CMUN"{project_code:"CMUN"
total:112.19},
"N2"{project_code:"N2"
total:4773.19}

---

您不需要更改查询。 只需更改foreach循环代码

foreach($Monthly_details as $key){
    if(empty($fetch[$key->project_code])){
        $fetch[$key->project_code]['total'] = 0;
    }
    $fetch[$key->project_code]['total'] += ($key->daily_rate * $key->days) - $key->absent - $key->late - $key->ut;
}
return $fetch;

//调用函数show（）的部分

---

伟大的但是，我如何才能显示总计属于哪个项目的值呢？。我想显示项目代码和总数量，您需要为其编写foreach循环，并访问项目代码作为结果的键，总数量作为调用work（）函数的位置的值。请检查我的最新答案。我可以把代码放在哪里？对不起，我只是求求你理解我：（我知道了..在我的vue中，我使用了

v-for=“（fetch，index）in paintdata”

，它显示了对象的索引是基于vue js的，你必须编写它。如果答案对你有帮助，请向上投票。

  public function show($id)
    {
 
        $Days = DB::table('payroll_monthly_attn_project')->where('payroll_monthly_id',$id)->where('assign','PAINTING')
        ->select('payroll_monthly_attn_project.wrk_id','payroll_monthly_attn_project.project_code','payroll_monthly_attn_project.assign','payroll_monthly_attn_project.days');

        $Monthly_details = DB::table('payroll_monthly_payable_details')->where('payroll_monthly_payable_details.payroll_monthly_id', $id)
                           ->select('payroll_monthly_payable_details.daily_rate','payroll_monthly_payable_details.late','payroll_monthly_payable_details.ut','payroll_monthly_payable_details.absent','days.*')
                           ->leftjoinSub($Days,'days',function($join){
                            $join->on('payroll_monthly_payable_details.wrk_id','=','days.wrk_id');    

                           })
                        ->get();

        $fetch = [];
        $grandTotal = 0;
        foreach($Monthly_details as $key){

            $grandTotal += ($key->daily_rate * $key->days) - $key->absent - $key->late - $key->ut;

        }
        $fetch['grandTotal'] = $grandTotal;

        return $fetch;
    }

{grandTotal: 4885.38}
grandTotal: 4885.38

"CMUN"{project_code:"CMUN"
total:112.19},
"N2"{project_code:"N2"
total:4773.19}

foreach($Monthly_details as $key){
    if(empty($fetch[$key->project_code])){
        $fetch[$key->project_code]['total'] = 0;
    }
    $fetch[$key->project_code]['total'] += ($key->daily_rate * $key->days) - $key->absent - $key->late - $key->ut;
}
return $fetch;

$results = work($id);
foreach($results as $projectCode => $total){
   echo $projectCode." total cost is: ".$total;
}