Php MYSQL使用一个连接两列并获取数据

修正！对不起，耽误了任何人的时间

我试图用PHP中的mysql将两个列连接起来

$result = $link->query('SELECT Software.*, 
Genre.Naam AS Genre, 
Console.Naam AS ConsoleNaam,
Draager.Naam AS MediumNaam,
Studio.Naam AS StudioNaam,
Publisher.Naam AS PublisherNaam
FROM Software
INNER JOIN Genre ON Genre.Genre_ID = Software.Genre_ID
INNER JOIN Console ON Console.Console_ID = Software.Console_ID
INNER JOIN Draager ON Draager.Draager_ID = Software.Medium_ID
INNER JOIN Company AS Studio ON Software.Studio_ID = Studio.Company_ID
INNER JOIN Company AS Publisher ON Software.Publisher_ID = Publisher.Company_ID
');

Table公司必须加入Table软件才能获得 公司名称

关于我必须更改到上面的脚本才能使其生效的任何提示 工作

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你打错了

JOIN

拼错为

JION

：

$result = $link->query('SELECT Software.*, 
Genre.Naam AS Genre, 
Console.Naam AS ConsoleNaam,
Draager.Naam AS MediumNaam,
Studio.Naam AS StudioNaam,
Publisher.Naam AS PublisherNaam
FROM Software
INNER JOIN Genre ON Genre.Genre_ID = Software.Genre_ID
INNER JOIN Console ON Console.Console_ID = Software.Console_ID
INNER JOIN Draager ON Draager.Draager_ID = Software.Medium_ID
/* Misspelled JOIN below *(/
INNER JOIN Company AS Studio ON Software.Studio_ID = Studio.Company_ID
INNER JOIN Company AS Publisher ON Software.Publisher_ID = Publisher.Company_ID
');

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我只想得到一个答案：

当关联表时，JION拼写为JOIN:D

$result = $link->query('SELECT Software.*, 
Genre.Naam AS Genre, 
Console.Naam AS ConsoleNaam,
Draager.Naam AS MediumNaam,
Studio.Naam AS StudioNaam,
Publisher.Naam AS PublisherNaam
FROM Software
INNER JOIN Genre ON Genre.Genre_ID = Software.Genre_ID
INNER JOIN Console ON Console.Console_ID = Software.Console_ID
INNER JOIN Draager ON Draager.Draager_ID = Software.Medium_ID
INNER JOIN Company AS Studio ON Software.Studio_ID = Studio.Company_ID
INNER JOIN Company AS Publisher ON Software.Publisher_ID = Publisher.Company_ID
');

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jion（Join）在你最后两个内部jion上的拼写…你能至少发布一个你表格的模式吗？哈哈！3个小时被浪费了，因为我有选择障碍。塔克斯！那么拼写是错误的还是还有更多的错误？如果对你有帮助，那就不是浪费；但是请选择对您帮助最大的回复旁边的复选标记。Thnx我忽略了这一点。修了三个小时就这样了：P