Php 包括刀片表单组件内部的身份验证
我有以下代码:Php 包括刀片表单组件内部的身份验证,php,laravel,laravel-blade,Php,Laravel,Laravel Blade,我有以下代码: <div class="col-lg-6 col-md-6 col-sm-12 col-xs-12"> @include('component.input',[ 'label' => 'Last Name', 'name' => 'last_name', 'type' => 'text', 'placeholder' => 'Li', 'class' =&g
<div class="col-lg-6 col-md-6 col-sm-12 col-xs-12">
@include('component.input',[
'label' => 'Last Name',
'name' => 'last_name',
'type' => 'text',
'placeholder' => 'Li',
'class' => '',
'errorMessage' => "required"
])
</div>
@包括('component.input'[
“标签”=>“姓氏”,
“姓名”=>“姓氏”,
'类型'=>'文本',
'占位符'=>'李',
“类”=>“”,
“errorMessage”=>“必需”
])
我想做一些类似的事情:
<div class="col-lg-6 col-md-6 col-sm-12 col-xs-12">
@include('component.input',[
'label' => 'Last Name',
'name' => 'last_name',
'type' => 'text',
'placeholder' => "{{Auth::user()->last_name}}"
'class' => '',
'errorMessage' => "required"
])
</div>
@包括('component.input'[
“标签”=>“姓氏”,
“姓名”=>“姓氏”,
'类型'=>'文本',
'占位符'=>“{{Auth::user()->last_name}”
“类”=>“”,
“errorMessage”=>“必需”
])
但是它返回的语法错误。在
@include
标记内时,您处于PHP上下文中,因此您可以直接使用facade:
<div class="col-lg-6 col-md-6 col-sm-12 col-xs-12">
@include('component.input',[
'label' => 'Last Name',
'name' => 'last_name',
'type' => 'text',
'placeholder' => Auth::user()->last_name,
'class' => '',
'errorMessage' => "required"
])
</div>
@包括('component.input'[
“标签”=>“姓氏”,
“姓名”=>“姓氏”,
'类型'=>'文本',
'占位符'=>Auth::user()->姓氏,
“类”=>“”,
“errorMessage”=>“必需”
])
在@include
标记内时,您处于PHP上下文中,因此您可以直接使用facade:
<div class="col-lg-6 col-md-6 col-sm-12 col-xs-12">
@include('component.input',[
'label' => 'Last Name',
'name' => 'last_name',
'type' => 'text',
'placeholder' => Auth::user()->last_name,
'class' => '',
'errorMessage' => "required"
])
</div>
@包括('component.input'[
“标签”=>“姓氏”,
“姓名”=>“姓氏”,
'类型'=>'文本',
'占位符'=>Auth::user()->姓氏,
“类”=>“”,
“errorMessage”=>“必需”
])