Php 将SQL查询转换为Zend DB Select

如何将此查询转换为Zend DB查询

SELECT t1.date, t1.station, t1.ftype, t1.price, t1.currency 
FROM fueling as t1  
INNER JOIN 
(SELECT MAX(t2.date) as maxdate, t2.station, t2.ftype 
FROM fueling as t2   
GROUP BY t2.station, t2.ftype) as t3
ON t1.date=t3.maxdate AND t1.station=t3.station AND t1.ftype=t3.ftype
where t1.station in ('GF112','GF11')
ORDER by t1.station,t1.ftype;

试试下面一个

$subselect = $this->db->select()
        ->from(array('t2'       => 'fueling'),
               array(
                    'maxdate' => 'MAX(t2.date)',
                    'station' => 't2.station',
                    'ftype' => 't2.ftype',
            ));

$select = $this->db->select()
            ->from(array('t1'       => 'fueling'),
                   array(
                        'date' => 't1.date',
                        'station' => 't1.station',
                        'ftype' => 't1.ftype',
                        'price'=>'t1.price',
                        'currency'=>'t1.currency'
                ))
            ->JOIN(array('t3'=>$subselect),'t1.date=t3.maxdate and t1.station=t3.station and t1.ftype=t3.ftype')
            ->Where('t1.station IN (?)', array('GF112','GF11')');

$results = $this->db->query($select)->fetchAll();

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我对你的子查询做了一点修改，现在一切都好了。多谢各位