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Php 我无法从代码中获得所需的结果_Php_Mysql_Sql_Datatable - Fatal编程技术网

Php 我无法从代码中获得所需的结果

Php 我无法从代码中获得所需的结果,php,mysql,sql,datatable,Php,Mysql,Sql,Datatable,我需要使用google Visualization api从mysql数据库创建dataTable。所以我这样做: try { $rez = $db->prepare("SELECT naziv FROM track_aktivnosti WHERE id_akt = :id_akt AND prvi=1 AND user_id=:user_id"); $rez->execute(array(':id_akt' => $_POST['id_akt'], ':user_

我需要使用google Visualization api从mysql数据库创建dataTable。所以我这样做:

try {

  $rez = $db->prepare("SELECT naziv FROM track_aktivnosti WHERE id_akt = :id_akt AND prvi=1 AND user_id=:user_id");
  $rez->execute(array(':id_akt' => $_POST['id_akt'], ':user_id' => $user_id));

  $kol = $rez->fetchAll();
  $rows = array();
  $rows1 = array();
  $table = array();
  $table = array();

  $rows[] = array('label' => 'Datum', 'type' => 'string');

  foreach ($kol as $r) {
    $rows[] = array('label' => (string) $r['naziv'], 'type' => 'string');
  }

  $table['cols'] = $rows;
  // convert data into JSON format
  $result = $db->prepare("SELECT datum FROM track_aktivnosti 
                                WHERE id_akt = :id_akt 
                                AND user_id=:user_id 
                                GROUP BY datum ORDER BY datum");

  $result->execute(array(':id_akt' => $_POST['id_akt'], ':user_id' => $user_id));
  $dates = $result->fetchAll();
  $final_result = array();

  $rows1 = array();
  foreach ($dates as $date) {

    $result = $db->prepare("SELECT vrednost, naziv 
                                    FROM track_aktivnosti 
                                    WHERE id_akt = :id_akt 
                                       AND datum = :datum  
                                       AND user_id= :user_id");

    $result->execute(array(':id_akt' => $_POST['id_akt'],
        ':datum' => $date['datum'],
        ':user_id' => $user_id));
    $m = array(array('v' => $date['datum']));
    foreach ($result as $r) {
      $m[] = array('v' => (int) $r['vrednost']);
    }
    $rows1[] = array('c' => $m);

    $table['rows'] = $rows1;
  }
} catch (PDOException $e) {
  echo 'ERROR: ' . $e->getMessage();
}
echo json_encode($table);
所以一切都很好,但这段代码会更改行值。。。从mysql数据库和前端dataTable中可以看到:所以dataTable是:(对于id_akt=82)

mysql数据库是:

所以,正如您在datatable中看到的,我得到的是
fdfdfd
值56,而不是76和类似值。。。我怎样才能解决这个问题

使用JS代码更新:

function drawTroskovnik() {
  var cssClassNames = {
    'headerRow': 'zaglavlje',
    'tableRow': 'red',
    'oddTableRow': 'red',
    'selectedTableRow': 'orange-background large-font',
    'hoverTableRow': 'prekoreda',
    'headerCell': 'gold-border',
    'tableCell': 'cell',
    'rowNumberCell': 'underline-blue-font'
  };

  // Create and populate the data table.
  var JSONObject = $.ajax({
    url: 'getTroskovnik.php', // make this url point to the data file
    dataType: 'json',
    data: {id_akt: ajdi},
    async: false,
    type: 'POST',
  }).responseText;

  var data = new google.visualization.DataTable(JSONObject, 0.5);

  for (var y = 0, maxrows = data.getNumberOfRows(); y < maxrows; y++) {
    for (var x = 1, maxcols = data.getNumberOfColumns(); x < maxcols; x++) {
      data.setValue(y, x, '<input vr="' + data.getValue(y, 0) + '" kol="' + data.getColumnLabel(x) + '" class="form-control costRedovi" value="' + data.getValue(y, x) + '">');
    }
  }
  for (var y = 0, maxrows = data.getNumberOfRows(); y < maxrows; y++) {
    data.setValue(y, 0, '<input class="span2 form-control" id="pocetak1" size="16" type="text" value="' + data.getValue(y, 0) + '" readonly>');
  }

  data.addColumn('string', '');
  for (var y = 0, maxrows = data.getNumberOfRows(); y < maxrows; y++) {
    var mc = data.getNumberOfColumns() - 1;
    data.setValue(y, mc, '<div data-toggle="tooltip" data-placement="top" title="Delete this day data"><i class="fa fa-trash-o" ></i></div>');
  }

  var table = new google.visualization.Table(document.getElementById('tpltroskovnik'));
  new google.visualization.events.addListener(table, 'ready', function() {
    $(".costRedovi").focusout(function() {
      var vrednost = $(this).val();
      var datum = $(this).attr('vr');
      var tabela = $(this).attr('kol');
      console.log(datum + " " + tabela + " " + vrednost);
      $.ajax({
        url: "updateCost.php",
        type: "POST",
        async: true,
        data: {ajdi: ajdi, datum: datum, tabela: tabela, vrednost: vrednost}, //your form data to post goes here as a json object
        dataType: "html",
        success: function(data) {
          console.log(data);
        },
      });
    });
  });

  table.draw(data, {'allowHtml': true, cssClassNames: {
      'headerRow': 'zaglavlje',
      'tableRow': 'red',
      'oddTableRow': 'red',
      'selectedTableRow': 'orange-background large-font',
      'hoverTableRow': 'prekoreda',
      'headerCell': 'gold-border',
      'tableCell': 'cell',
      'rowNumberCell': 'underline-blue-font'}
  });
};
函数drawTroskovnik(){ 变量cssClassNames={ “headerRow”:“zaglavlje”, “tableRow”:“红色”, “oddTableRow”:“红色”, “selectedTableRow”:“橙色背景大字体”, “hoverTableRow”:“prekoreda”, “headerCell”:“黄金边界”, “tableCell”:“cell”, “rowNumberCell”:“下划线蓝色字体” }; //创建并填充数据表。 var JSONObject=$.ajax({ url:'getroskovnik.php',//使此url指向数据文件 数据类型:“json”, 数据:{id_akt:ajdi}, async:false, 键入:“POST”, }).responseText; var data=新的google.visualization.DataTable(JSONObject,0.5); 对于(变量y=0,maxrows=data.getNumberOfRows();y在您提供的PHP代码中,列名和行值之间没有关联。因此,哪些列中的值取决于从数据库中提取数据的顺序,该顺序可能基于性能或插入顺序,并且可能因查询而异。为了获得可预测的顺序,您需要在查询中指定要提取的顺序。需要对齐的两个查询是:提取名称的查询和提取值的查询

缺乏可预测的秩序:

$rez = $db->prepare("SELECT naziv FROM track_aktivnosti WHERE id_akt = :id_akt AND prvi=1 AND user_id=:user_id");

...

$result = $db->prepare("SELECT vrednost, naziv FROM track_aktivnosti WHERE id_akt = :id_akt AND datum = :datum AND user_id= :user_id");

ORDER BY naziv
添加到每个结果的末尾,以将结果排序为可预测的对齐方式,然后将其正确加载到关联数组中,后面是JSON对象

下面是您的代码的一个调整版本,它解决了一些其他非关键问题:

<?php

try {

    $res = $db->prepare('SELECT naziv FROM track_aktivnosti WHERE id_akt = :id_akt AND user_id = :user_id AND prvi = 1 ORDER BY naziv');
    $res->execute(array(':id_akt' => $_POST['id_akt'], ':user_id' => $user_id));
    $kol = $res->fetchAll();

    $rows = array();
    $table = array();

    $rows[] = array('label' => 'Datum', 'type' => 'string');

    foreach ($kol as $r) {
        $rows[] = array('label' => (string) $r['naziv'], 'type' => 'string');
    }

    $table['cols'] =  $rows;

    $res = $db->prepare('SELECT datum FROM track_aktivnosti WHERE id_akt = :id_akt AND user_id = :user_id GROUP BY datum ORDER BY datum');
    $res->execute(array(':id_akt' => $_POST['id_akt'], ':user_id' => $user_id));
    $dates = $res->fetchAll();

    $rows = array();

    foreach($dates as $date){

       $res = $db->prepare('SELECT vrednost FROM track_aktivnosti WHERE id_akt = :id_akt AND user_id = :user_id AND datum = :datum  ORDER BY naziv');
       $res->execute(array(':id_akt' => $_POST['id_akt'], ':user_id' => $user_id, ':datum' => $date['datum']));
       $vals = $res->fetchAll();

       $m = array( array( 'v' => $date['datum'] ) );

       foreach($vals as $r) {
           $m[] = array('v' => (int) $r['vrednost']);
       }
       $rows[] =  array('c' => $m);

       $table['rows'] = $rows;
    }

} catch(PDOException $e) {
    echo 'ERROR: ' . $e->getMessage();
}

echo json_encode($table);

?>


检查生成的数组,然后检查代码逻辑代码逻辑是否正常,但我在前端得到了不同的结果…您能检查json是否如下所示吗<代码>{“cols”:[{“label”:“Datum”,“type”:“string”},{“label”:“fdfdfd”,“type”:“string”},{“label”:“IMT 510 td”,“type”:“string”},,“rows”:[{“c”:[{“v”:“2013-04-01”},{“v”:1},{“v”:5},{“c”:[{“v”:“2014-04-16},{“v”:76},{“v”:56},{“c”:“v”:“v”:“v”:“2013-04-04-01”},{“v”:1},{“v”:1},{“v”:5},{“v”:5},},{“v”:4},{。我尝试重新创建一切,得到了json数据并将这些数据转储到Google的DataTable中,它显示了我认为正确的表。也许你应该发布你的javascript代码?我用JS代码更新了这个问题,请用一个描述性的标题重命名这个标题,比如“使用google Visualization api从mysql数据库创建dataTable”,这样会更好地吸引那些能提供帮助的人。没错,anser,但是为什么你要使用$\u GET,我使用$\u POST我认为使用POST更好?我临时更改了它以便于故障排除(这样我就可以在URL中使用必要的变量自行加载页面),但在这里发布时忘记将其更改回POST。我修复了它。它容易受到sql注入的攻击吗?不,检查这个:“准备好的语句的参数不需要被引用;驱动程序会自动处理它。”太棒了!