Php 如何在codeigniter中使用或类似于连接表

这是我的代码，它给了我错误的结果。有谁能说出正确的解决办法吗

$this->db->select('tbl_member.*,tbl_country.country_name,tbl_city.city_name');
    $this->db->like('tbl_member.first_name',$_GET['keyword']);
    $this->db->or_like('tbl_member.last_name',$_GET['keyword']);
    $this->db->where('tbl_member.status','Active');
    $this->db->where('tbl_member.approve_status','Active');
    $this->db->where('tbl_member.account_close_by_member','No');
    $this->db->where('tbl_member.account_delete_by_member','No');
    $this->db->order_by('tbl_member.membership_type','Desc');
    $this->db->order_by('tbl_member.membership_expire','Desc');


    $where="( tbl_member.member_type='Independent' || tbl_member.member_type='Agency-Profile')";
    $this->db->where($where);
    $this->db->or_like('tbl_country.country_name',$_GET['keyword']);
    $this->db->or_like('tbl_city.city_name',$_GET['keyword']);
    $this->db->join('tbl_country','tbl_country.ct_id=tbl_member.country_id');
    $this->db->join('tbl_city','tbl_city.c_id=tbl_member.city');
    $query=$this->db->get($this->tablename);
    $record=$query->result();

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我希望你在找什么。是的，永远不要离开。你能提供更多的信息吗？问了这个问题后你得到了什么？