用于在网页上搜索单词的PHP脚本

有人能告诉我如何改变以下PHP脚本说“发现”如果该网站有“站起来”一词，如果它没有说“没有发现”

<?php
$data = file_get_contents('http://www.stutteringjohnsmmith.com/#/0');
$regex = '/Page 1 of (.+?) results/';
preg_match($regex,$data,$match);
var_dump($match);
echo $match[1];
?>

笑？

---

您正在使用wordpress域(http://stutteringjohnsmith.wordpress.com/)

以下工作将起作用：

$data = file_get_contents('http://stutteringjohnsmith.wordpress.com/');
$regex = '/standup/';    

if (preg_match($regex, $data)) {
    echo "found";
} else {
    echo "not found";
}

<?php
$text = file_get_contents('http://www.stutteringjohnsmith.com/#/0');
echo (stristr ($text, 'standup')) ? 'found' : 'not found';
?>

$data = file_get_contents('http://stutteringjohnsmith.wordpress.com/');
$regex = '/standup/';    

if (preg_match($regex, $data)) {
    echo "found";
} else {
    echo "not found";
}