Php 帮助我在Wordpress的模式标记中显示Post数据

我将为模式标记指定自定义字段，但它没有显示值。我们将感谢您在这个问题上的帮助

注意：自定义文件显示的数据超出了模式JSON代码。我只想在模式标记中显示数据。多谢各位

代码示例

<?php 

$hiring_organization = get_field('hiring_organization');
$organization_url = get_field('organization_url');
$online_apply = get_field('online_apply'); 
$form = get_field('form'); 
$industry_type = get_field('industry_type'); 
$employment_type = get_field('employment_type'); 
$job_published_date = get_field('job_published_date'); 
$job_expiry_date = get_field('job_expiry_date'); 
$job_location = get_field('job_location'); 
$address = get_field('address'); 
$postal_code = get_field('postal_code'); 
$min_salary = get_field('min_salary'); 
$max_salary = get_field('max_salary'); 
$responsibilities = get_field('responsibilities'); 
$skills = get_field('skills'); 
$qualification = get_field('qualification'); 
$experience = get_field('experience'); 
$salary_base = get_field('salary_base'); 

?>



<!-- START SCHEMA -->
<script type="application/ld+json">
{
  "@context": "https://schema.org/",
  "@type": "JobPosting",
  "title": "<?php the_title(); ?>",
  "description": "<?php the_content(); ?>",
  "hiringOrganization" : {
    "@type": "Organization",
    "name": "<?php $hiring_organization; ?>",
    "sameAs": "<?php $organization_url; ?>"
  },
  "industry": "<?php $industry_type; ?>",
  "employmentType": "<?php $employment_type; ?>",
  "datePosted": "<?php $job_published_date; ?>",
  "validThrough": "<?php $job_expiry_date; ?>",
  "jobLocation": {
    "@type": "Place",
    "address": {
      "@type": "PostalAddress",
      "streetAddress": "<?php $address; ?>",
      "addressLocality": "<?php $job_location; ?>",
      "postalCode": "<?php $postal_code; ?>",
      "addressCountry": "PK"
    }
  },
  "baseSalary": {
    "@type": "MonetaryAmount",
    "currency": "PKR",
    "value": {
      "@type": "QuantitativeValue",
      "minValue": <?php $min_salary; ?>,
      "maxValue": <?php $max_salary; ?>,
      "unitText": "<?php $salary_base; ?>"
    }
  },
  "responsibilities": "<?php $responsibilities; ?>",
  "skills": "<?php $skills; ?>",
  "qualifications": "<?php $qualification; ?>",
  "educationRequirements": "<?php $qualification; ?>",
  "experienceRequirements": "<?php $experience; ?>"
}
</script>
<!-- END SCHEMA -->

{
“@context”：”https://schema.org/",
“@type”：“职位发布”，
“名称”：“名称”，
“说明”：“，
“雇佣组织”：{
“@type”：“组织”，
“名称”：“，
“sameAs”：”
},
“工业”：“，
“employmentType”：“，
“已发布日期”：“，
“有效通过”：“，
“工作地点”：{
“@type”：“Place”，
“地址”：{
“@type”：“PostalAddress”，
“街道地址”：“，
“地址地点”：“地址地点”，
“postalCode”：“，
“地址国家”：“主键”
}
},
“基本工资”：{
“@type”：“MonetaryAmount”，
“货币”：“PKR”，
“价值”：{
“@type”：“QuantitativeValue”，
“minValue”：，
“最大值”：，
“unitText”：”
}
},
“责任”：“，
“技能”：“，
“资格”：“，
“教育要求”：“，
“体验要求”：
}

请记住_title（）；和_内容（）；正在显示数据。只有自定义填充的数据不显示。谢谢

问题解决了。 我忘记了变量之前的echo。php代码只需要在变量之前使用echo，如。

---

“name”：“

而不是

“name”：“

您必须回显您的变量