Php 添加换行符时出现SQL错误1064

我有一个我想处理的查询，所以我以一种更容易阅读的方式格式化了它。但是，当我刷新页面时，我收到错误1064。我唯一做的就是添加换行符。即使我只添加了一个换行符，我也会得到这个错误

以下是原始查询：

$listing_sql = "select " . $select_column_list . " p.products_id, p.products_model, p.manufacturers_id, p.products_price, p.products_tax_class_id, IF(s.status, s.specials_new_products_price, NULL) as specials_new_products_price, IF(s.status, s.specials_new_products_price, p.products_price) as final_price from " . TABLE_PRODUCTS_DESCRIPTION . " pd, " . TABLE_PRODUCTS . " p left join " . TABLE_MANUFACTURERS . " m on p.manufacturers_id = m.manufacturers_id left join " . TABLE_SPECIALS . " s on p.products_id = s.products_id, " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c where p.products_status = '1' and p.products_id = p2c.products_id and pd.products_id = p2c.products_id and pd.language_id = '" . (int)$languages_id . "' and p2c.categories_id = '" . (int)$current_category_id . "'";

只需在前面添加1或2个换行符，如下所示：

$listing_sql = "select " . $select_column_list . " p.products_id, p.products_model, p.manufacturers_id, p.products_price, p.products_tax_class_id, IF(s.status, s.specials_new_products_price, NULL) as specials_new_products_price, IF(s.status, s.specials_new_products_price, p.products_price) as final_price 

from " . TABLE_PRODUCTS_DESCRIPTION . " pd, " . TABLE_PRODUCTS . " p left join " . TABLE_MANUFACTURERS . " m on p.manufacturers_id = m.manufacturers_id left join " . TABLE_SPECIALS . " s on p.products_id = s.products_id, " . TABLE_PRODUCTS_TO_CATEGORIES . " p2c where p.products_status = '1' and p.products_id = p2c.products_id and pd.products_id = p2c.products_id and pd.language_id = '" . (int)$languages_id . "' and p2c.categories_id = '" . (int)$current_category_id . "'";

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导致出现错误我正在使用带有mysql版本5.5.16和php版本5.2.2 appache 2.0.63的wamp server，这是因为您实际上在查询中添加了一个\n或一个很大的间隙

如果您以最终价格停止报价，然后添加换行符，然后继续字符串从'。表…，您应该会发现错误没有发生

直接在查询后键入此代码，您将看到错误

echo $listing_sql;
exit();

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你把换行符放在字符串中间，MySQL服务器不喜欢。将查询拆分为多行的明智方法是：

$listing_sql = "select " . $select_column_list . 
" p.products_id, p.products_model, p.manufacturers_id, p.products_price, " .
"p.products_tax_class_id, IF(s.status, s.specials_new_products_price, NULL) as " .
"specials_new_products_price, IF(s.status, s.specials_new_products_price, " .
"p.products_price) as final_price from " . 
TABLE_PRODUCTS_DESCRIPTION . " pd, " . TABLE_PRODUCTS . " p left join " . 
TABLE_MANUFACTURERS . " m on p.manufacturers_id = m.manufacturers_id left join " . 
TABLE_SPECIALS . " s on p.products_id = s.products_id, " . 
TABLE_PRODUCTS_TO_CATEGORIES . " p2c where p.products_status = '1' and " .
"p.products_id = p2c.products_id and pd.products_id = p2c.products_id and " .
"pd.language_id = '" . (int)$languages_id . "' and p2c.categories_id = '" . 
(int)$current_category_id . "'";

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这不是答案，但为什么在int表达式周围使用引号呢？查看执行查询的代码可能也会有所帮助。这不是我的查询，但我相信这是因为它是一个被调用到querySee中的php变量，实际上查询使用WHERE x='3'而不是WHERE x=3形式；但是，如果x是int域，那么后者是很好的，我想它是。但不管怎样：您是否尝试在其行的“from”之前插入一个空格？即，将^from替换为^from。