JSON完整循环（PHP）

我已经简化到最简单的形式，但仍然步履蹒跚……我花了30多个小时进行研究和测试。根据所有从不显示整个圆圈超过15°的帖子，这应该是非常容易的

我想：

将查询参数（JSON格式）从Android手机发送到WAMP服务器……这可能相当于本地SQLite表的一个完整转储，因此查询字符串不会剪切它

让WAMP服务器读取JSON数据，制定SQL查询并提交到mySQL数据库

将响应打包为JSON数据（从简单的“OK”到完整的表转储）

将响应包返回到Android手机

这已经是一个功能齐全的WAMP应用程序，我想集成Android access。出于这个原因，我真的希望避免使用AJAX，因为我希望保持与已有内容的一致性

我已经将其简化为最简单的循环，并且遇到了障碍。我使用send.php将一些JSON数据发布到receive.php。此时，我只需要receive.php读取数据并将其发送回（稍微修改）send.php

send.php正在正确读取从receive.php发送的股票JSON。我只是无法得到任何生命迹象，receive.php甚至无法识别发送给它的JSON

请不要把我引向cURL……从我所发现的关于Android和JSON的所有信息来看，cURL是一个切线，它将把我送回一个完整的无功能状态

Apache2.2.22，PHP5.4.3

就像我说的，我把它简化成最简单的形式来演示一个完整的圆

send.php：

<?php
$url = "http://192.168.0.102:808/networks/json/receive.php";
$data = array(
        'param1'      => '12345',
        'param2'    => 'fghij'
);
$json_data = json_encode($data);

$options = array(
        'http' => array(
                'method'  => 'POST',
                'content' => $json_data,
                'header'=>  "Content-Type: application/json\r\n" .
                "Accept: application/json\r\n" .
                'Content-Length: ' . strlen($json_data) . "\r\n"
        )
);

$context  = stream_context_create( $options );
$result = file_get_contents( $url, false, $context );

$response = json_decode( $result , true);
echo '[' . $response['param1'] . "]\n<br>";
//THIS WORKS!  send.php displays "Initialized"
?>

receive.php

<?php
$newparam = 'Initialized';
//HERE I NEED TO read the JSON data and do something

$data = array(
        'param1'      => $newparam,
        'param2'    => 'pqrst'
);

header('Content-type: application/json');
echo json_encode($data);
?>

<?php
//K.I.S.S. - Retrieve the incoming JSON data, decode it and send one value 
//back to send.php

//Grab the incoming JSON data (want error correction)
//THIS IS THE PART I WAS MISSING
$data_from_send_php = file_get_contents('php://input');

//Decode the JSON data
$json_data = json_decode($data_from_send_php, true);

//CAN DO:  read querystrings (can be used for user auth, specifying the 
//requestor's intents, etc)

//Retrieve a nugget from the JSON so it can be sent back to send.php
$newparam = $json_data["param2"];

//Prep the JSON to send back
$data = array(
        'param1'      => $newparam,
        'param2'    => 'pqrst'
);

//Tell send.php what kind of data it is receiving
header('Content-type: application/json');

//Give send.php the JSON data
echo json_encode($data);
?>

---

正如所有不完整的解释中所述，这其实很容易……我终于完成了整个循环

我选择简单来证明我可以周而复始，现在我已经做到了

send.php

<?php 
//The URL of the page that will:
//  1. Receive the incoming data
//  2. Decode the data and do something with it
//  3. Package the results into JSON
//  4. Return the JSON to the originator
$url = "http://192.168.0.102:808/networks/json/receive.php";

//The JSON data to send to the page (above)
$data = array(
        'param1'      => 'abcde',
        'param2'    => 'fghij'
);
$json_data = json_encode($data);

//Prep the request to send to the web site
$options = array(
        'http' => array(
                'method'  => 'POST',
                'content' => $json_data,
                'header'=>  "Content-Type: application/json\r\n" .
                "Accept: application/json\r\n"
        )
);
$context  = stream_context_create( $options );

//Make the request and grab the results
$result = file_get_contents( $url, false, $context );

//Decode the results
$response = json_decode( $result , true);

//Do something with the results
echo '[' . $response['param1'] . "]\n<br>";
?>

receive.php

<?php
$newparam = 'Initialized';
//HERE I NEED TO read the JSON data and do something

$data = array(
        'param1'      => $newparam,
        'param2'    => 'pqrst'
);

header('Content-type: application/json');
echo json_encode($data);
?>

<?php
//K.I.S.S. - Retrieve the incoming JSON data, decode it and send one value 
//back to send.php

//Grab the incoming JSON data (want error correction)
//THIS IS THE PART I WAS MISSING
$data_from_send_php = file_get_contents('php://input');

//Decode the JSON data
$json_data = json_decode($data_from_send_php, true);

//CAN DO:  read querystrings (can be used for user auth, specifying the 
//requestor's intents, etc)

//Retrieve a nugget from the JSON so it can be sent back to send.php
$newparam = $json_data["param2"];

//Prep the JSON to send back
$data = array(
        'param1'      => $newparam,
        'param2'    => 'pqrst'
);

//Tell send.php what kind of data it is receiving
header('Content-type: application/json');

//Give send.php the JSON data
echo json_encode($data);
?>

---

在receive.php内部使用
error\u log（）
查找生命迹象。@user2147564在读取（在receive.php中）发送的json数据时尝试json\u decode（$data）。isset（$\u POST）返回true，但似乎不包含任何内容。如果我尝试访问$_POST['content']，从send.php发送的标题来看，这似乎是合乎逻辑的，那么这里什么都没有（错误）。我知道我需要对json进行解码（$data_from_send_php），但是如何检索传入的json数据呢？在进一步测试后，receive.php以数组的形式接收$_POST，但count（$_POST）=0…问题（开始）是send.phpOnly花了几百篇文章才找到它…send实际上还可以，它正确地将json数据发送到receive.php。JSON数据可通过“$data\u from\u send\u php=file\u get\u contents（'php://input');"