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Php 警告:mysqli_fetch_assoc()要求参数1为mysqli_结果,字符串在_Php_Mysqli - Fatal编程技术网

Php 警告:mysqli_fetch_assoc()要求参数1为mysqli_结果,字符串在

Php 警告:mysqli_fetch_assoc()要求参数1为mysqli_结果,字符串在,php,mysqli,Php,Mysqli,正在尝试获取表中的最后一行,但引发错误 '警告:mysqli_fetch_assoc()希望参数1为 mysqli_结果,字符串在' 您需要传递查询的结果,而不是查询字符串 $sql = "SELECT * FROM list ORDER BY id DESC LIMIT 1"; $recent = mysqli_query($connetion, $sql); 您忘记使用该语句来运行查询 $results=mysqli_query($conn,$recents) 您的查询不返回任何记录,请

正在尝试获取表中的最后一行,但引发错误

'警告:mysqli_fetch_assoc()希望参数1为 mysqli_结果,字符串在'


您需要传递查询的结果,而不是查询字符串

$sql = "SELECT * FROM list ORDER BY id DESC LIMIT 1";
$recent = mysqli_query($connetion, $sql);

您忘记使用该语句来运行查询

$results=mysqli_query($conn,$recents)

您的查询不返回任何记录,请检查数据库连接并回显查询。在尝试从结果中获取行之前,您需要执行查询。哪里是
mysqli\u query()
???
$results=mysqli_query($conn,$recents)