Php 显示复选框数组值
我试图在我的复选框数组中循环并显示每个元素的值,但它返回0,真正的值是电子邮件。(lucas.ro****@gmail.com)和(thatian****@gmail.com) 这是我的密码:Php 显示复选框数组值,php,arrays,checkbox,show,Php,Arrays,Checkbox,Show,我试图在我的复选框数组中循环并显示每个元素的值,但它返回0,真正的值是电子邮件。(lucas.ro****@gmail.com)和(thatian****@gmail.com) 这是我的密码: <form method="POST" action="testeEmail.php"> <table id="tableEmail" class="table table-striped table-bordered">
<form method="POST" action="testeEmail.php">
<table id="tableEmail" class="table table-striped table-bordered">
<tr>
<td>Email</td>
<td width="5%">Enviar?</td>
<td class="centro">Já recebido</td>
<td width="10%"> <button type="submit" class="btn btn-success"><span class="glyphicon glyphicon-send"></span> Enviar (Os útimos não enviados)</button></td>
</tr>
<?
include("conexao.php");
mysql_query("SET NAMES 'utf8'");
mysql_query("SET character_set_connection=utf8");
mysql_query("SET character_set_client=utf8");
mysql_query("SET character_set_results=utf8");
$resultEmail = mysql_query("SELECT id,email,recebido FROM Newsletter");
if (mysql_num_rows($resultEmail) > 0) {
while ($rowEmail = mysql_fetch_assoc($resultEmail)){?>
<tr>
<td><? echo $rowEmail['email'] ?></td>
<td class="centro">
<input type="checkbox" name="box[]" value="<? echo $rowEmail['email'] ?>" <? if($rowEmail['recebido'] == 1){}else{ echo "checked"; } ?>>
</td>
<td class="centro"><? if($rowEmail['recebido'] == 1){ echo "<font color='green'>Sim</font>";}else{ echo "<font color='#d9534f'>Não</font>"; } ?></td>
<td>
<a href="deletarEmail.php?idEmail=<? echo $rowEmail['id'] ?>" class="btn btn-danger"><span class="glyphicon glyphicon-remove" aria-hidden="true"></span> DELETAR</a>
</td>
</tr>
<?}
}
mysql_free_result($resultEmail);
mysql_close($conecta);?>
</table>
</form>
电子邮件
嫉妒?
贾里切比多
Enviar(Osútimos não enviados)
>
首先:安全警告。在php.net网站上有一个红色框,告诉你
mysql\函数已弃用。例如使用PDO库:
这是必须的
要检查帖子是否正常,只需使用:print\r($\u post)
。它应该显示每个发布的值。但是,代码中存在逻辑问题。请看这里:
foreach($_POST['box'] as $box){
if(isset($box)){
//$dest = $box;
echo $box;
} else{
}
}
如果($\u POST['box']=array())
,我的意思是空数组,则永远不会到达foreach(因为没有each)因此无需在foreach循环内检查isset。你应该这样做:
if(isset($_POST['box']) && is_array($_POST['box'])) {
foreach($_POST['box'] as $box){
var_dump($box); // Always use var_dump for testing echo...
}
else {
// box'es were not posted
}
我希望这是明确的,并将帮助你一点
还要记住,复选框有点特殊。请看这里:
第一个答案应该对您非常有用。如果它返回的是null
,您可能需要检查查询返回的内容。在我看来,这似乎是
使用print\r($\u POST)
查看脚本中是否有任何内容。
if(isset($_POST['box']) && is_array($_POST['box'])) {
foreach($_POST['box'] as $box){
var_dump($box); // Always use var_dump for testing echo...
}
else {
// box'es were not posted
}