类方法中的PHP Time（）函数

我有一个带有函数

date

的类

Convert

：

<?php
    class Convert{
        public static function datum($timestamp = time()){
            //When $timestamp isn't set use php function time()

           return(date("N" , $timestamp));
        }
    }
?>

//run method
Convert::datum();

更改

class Convert{
    public static function datum($timestamp = time()){ // <-- no functions allowed in here
        //When $timestamp isn't set use php function time()

       return(date("N" , $timestamp));
    }
}

声明函数时，参数只能接受空数据类型或数据。参数不能设置为接受函数的返回，也不能是动态的

好

public static function datum($timestamp = NULL){
public static function datum($timestamp = 13524564){
public static function datum($timestamp = '423432'){
public static function datum($timestamp = array()){
public static function datum($timestamp = FALSE){
public static function datum($timestamp = TRUE){

public static function datum($timestamp = time()){
public static function datum($timestamp = (8*2)){
public static function datum($timestamp = $this->someValFromThisClass){
public static function datum($timestamp = 123, $new = $timestamp){

坏的

public static function datum($timestamp = NULL){
public static function datum($timestamp = 13524564){
public static function datum($timestamp = '423432'){
public static function datum($timestamp = array()){
public static function datum($timestamp = FALSE){
public static function datum($timestamp = TRUE){

public static function datum($timestamp = time()){
public static function datum($timestamp = (8*2)){
public static function datum($timestamp = $this->someValFromThisClass){
public static function datum($timestamp = 123, $new = $timestamp){

不能将函数作为默认值。把它移到你的方法中。你是什么意思？他的意思是
time（）
是一个函数，你不能将函数作为默认值，这是你目前拥有的。不客气。有关更全面的说明，请参见我的更新