从数组PHP导出数据
我有一个很简单的问题要问你 我有一个像这样的数组从数组PHP导出数据,php,arrays,Php,Arrays,我有一个很简单的问题要问你 我有一个像这样的数组 array( (int) 0 => array( 'id' => '14', 'user_id' => '39', 'price_id' => '6', 'count' => '3', 'created' => '2015-11-10 16:42:26' ), (int) 1 => array( 'id' => '20', 'user_id'
array(
(int) 0 => array(
'id' => '14',
'user_id' => '39',
'price_id' => '6',
'count' => '3',
'created' => '2015-11-10 16:42:26'
),
(int) 1 => array(
'id' => '20',
'user_id' => '47',
'price_id' => '6',
'count' => '1',
'created' => '2015-11-10 18:00:44'
),
(int) 2 => array(
'id' => '22',
'user_id' => '45',
'price_id' => '6',
'count' => '1',
'created' => '2015-11-10 18:16:22'
),
(int) 3 => array(
'id' => '24',
'user_id' => '35',
'price_id' => '6',
'count' => '2',
'created' => '2015-11-10 18:19:32'
)
);
我需要将其导出为一个新数组,在这里我可以看到第一个数组的3倍,因为“count”是3
我做了一个简单的从我的表中选择*,其中price\u id=6
但当我尝试创建3倍于相同数组时,它开始变得混乱
$participants = array();
for ($i=0; $i < sizeof($giveaway) ; $i++) {
$participants[] = $giveaway[$i]['Winners'];
$nbreparticipations = $giveaway[$i]['Winners']['count'];
for ($j=0; $j < sizeof($nbreparticipations); $j++) {
$participants[$i][] = $j;
}
}
$participants=array();
对于($i=0;$i
最后,它应该是这样的()
身份证件
用户id
1.
39
2.
39
3.
39
4.
47
5.
45
6.
35
7.
35
我刚刚看到了我的错误
这是我的新代码
$participants = array();
$new_participations = array();
for ($i=0; $i < sizeof($giveaway) ; $i++) {
$participants[] = $giveaway[$i]['Winner'];
$nbreparticipations = $giveaway[$i]['Winner']['count'];
$user_id = $giveaway[$i]['Winner']['user_id'];
for ($j=0; $j < $nbreparticipations; $j++) {
$new_participations[] = $giveaway[$i]['Winner'];
}
}
$participants=array();
$new_participations=array();
对于($i=0;$i
我首先为第二个for()创建一个新数组()
之后,我得到了参与人数,但在第二次for()时,我使用了sizeof()。但此函数仅适用于数组
$participants = array();
$new_participations = array();
for ($i=0; $i < sizeof($giveaway) ; $i++) {
$participants[] = $giveaway[$i]['Winner'];
$nbreparticipations = $giveaway[$i]['Winner']['count'];
$user_id = $giveaway[$i]['Winner']['user_id'];
for ($j=0; $j < $nbreparticipations; $j++) {
$new_participations[] = $giveaway[$i]['Winner'];
}
}