Php 在if/else中使用in_数组和日期时出现问题

我正在试验PHP的功能和特性

根据我在手册中读到的内容，我无法理解为什么我的代码返回if语句的else部分。如果日期（'D'）返回Tue为什么不运行If部分

<?php

date_default_timezone_set('UTC');

$weekdays = array("Mon", "Tue", "Wed", "Thur", "Fri", "Sat", "Sun");

$today = date('D');

if(in_array("Mon", "Tue", "Wed", "Thur", "Fri", $weekdays) == $today)
   {
         echo "It's" . " ";
         echo $today;
         echo " " . "Get out of bed and go to work";
    }else{
         echo "Do whatever you want becuase it's" . " ";
         echo $today;
};
?>

谁能告诉我语法有什么问题吗

if(in_array($today, $weekdays))
   {
         echo "It's" . " ";
         echo $today;
         echo " " . "Get out of bed and go to work";
    }else{
         echo "Do whatever you want becuase it's" . " ";
         echo $current_day;
};

---

手动使用数组中的

功能

如果您想知道
$today
是否为工作日，您可以执行以下操作：

$weekdays = array("Mon", "Tue", "Wed", "Thur", "Fri");
if(in_array($today, $weekdays)) {
   ...
}

$weekdays = array("Mon", "Tue", "Wed", "Thur", "Fri");
if(in_array($today, $weekdays)) {
   ...
}