Php 日期差

我有两个字符串格式的日期，我想从这两个日期字符串计算这些东西。 1年差额 比如说

$date1 = "20/04/2002";
$date2= "20/04/2010";
$five_yers_back = <Five years back that is 2005>

同样地

$date2= "20/05/2010";
$a_week = "< seven days back from date2 >";

Plz帮助

使用strotime+date

http://pl2.php.net/manual/en/function.strtotime.php
http://pl2.php.net/manual/en/function.date.php

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我肯定会有课程为你做这件事。但作为一名C程序员，我更喜欢tm结构的基础知识。这里的PHP等效示例

<?php

$d1 = "20/04/2002";
$d1rec = strptime( $d1, "%d/%m/%Y" );
$sec = 0;
$min = 0;
$hour = 0;
$day = $d1rec["tm_mday"];
$mon = $d1rec["tm_mon"] + 1;  # Because tm_mon is 0-11
$year = $d1rec["tm_year"];
print( "DATE: " . strftime( "%d/%m/%Y\n"
              , mktime($hour,$min,$sec,$mon,$day,$year) ) );
print( "+1WK: " . strftime( "%d/%m/%Y\n"
              , mktime($hour,$min,$sec,$mon,$day+7,$year) ) );
print( "+2WK: " . strftime( "%d/%m/%Y\n"
              , mktime($hour,$min,$sec,$mon,$day+14,$year) ) );
print( "+1YR: " . strftime( "%d/%m/%Y\n"
              , mktime($hour,$min,$sec,$mon,$day,$year+1) ) );
print( "-6MO: " . strftime( "%d/%m/%Y\n"
              , mktime($hour,$min,$sec,$mon-6,$day,$year) ) );

?>

所以基本上

使用strtime将字符串解析为结构数组 将数组分解为变量 使用mktime将修改后的变量重新组合为时间整数，并进行月/年包装 使用strftime返回字符串