来自PHP重定向的Android MediaPlayer流媒体无法运行！

我工作的那家公司正在开发一款Android应用程序，它可以从web上的URL播放视频文件。这个 视频URL是PHP脚本的一个参数，可对其进行正确编码并重定向到编码视频，如下所示：

header('Content-Type: video/'.$format);
header('Location:'.$output_video);

其中，

$output\u video

是编码视频的URL（如果我们在浏览器中使用此URL，它会工作），而

$format

是视频格式

但是，当我尝试使用流模式从API演示中执行时，会出现如下错误：

MediaPlayer Command PLAYER INIT completed with an error or info PVMFErrCorrupt
MediaPlayer error (1. -10)
MediaPlayer Error (1.-10)

如果我们在PHP脚本中硬编码URL和格式，它也不起作用，但会出现不同的错误：

MediaPlayer info/warning (1. 28)
MediaPlayer Info (1 .28)

有人知道如何解决这个问题吗

---

提前谢谢

响应是您试图在MediaPlayer中传输的文件，您的URL必须是，例如：

rtsp://v1.cache5.c.youtube.com/CjYLENy73wIaLQkUvSkxA_7UKxMYESARFEIJbXYtZ29vZ2xlSARSBXdhdGNoYIPXxZHky7m5Rgw=/0/0/0/video.3gp

（请尝试使用此URL）

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使用rtsp协议和.3gp视频文件时，我遇到了同样的问题。android MediaPlayer无法处理重定向，因此您必须找到php脚本将您重定向到的位置，并按照Jeorgesys的解释为其提供rtsp URL

我能够通过执行HttpGet而不遵循任何重定向来解决这个问题，然后从“Location”Http头中提取rtspurl。如果你有多个重定向，你会有一点麻烦，但幸运的是在我的情况下，我只需要担心一个重定向

public static String resolveRedirect(String url) throws ClientProtocolException, IOException {
    HttpParams httpParameters = new BasicHttpParams();
    HttpClientParams.setRedirecting(httpParameters, false);

    HttpClient httpClient = new DefaultHttpClient(httpParameters);      
    HttpGet httpget = new HttpGet(url);
    HttpContext context = new BasicHttpContext();

    HttpResponse response = httpClient.execute(httpget, context);

    // If we didn't get a '302 Found' we aren't being redirected.
    if (response.getStatusLine().getStatusCode() != HttpStatus.SC_MOVED_TEMPORARILY)
        throw new IOException(response.getStatusLine().toString());

    Header loc[] = response.getHeaders("Location");
    return loc.length > 0 ? loc[0].getValue() : null;
}

---

下面是一个简单的例子

public class StreamVideo extends Activity
{
VideoView video;
@Override
protected void onCreate(Bundle savedInstanceState)  
{       
    super.onCreate(savedInstanceState);
    setContentView(R.layout.streamvideo);
    video = (VideoView)findViewById(R.id.videoView1);
    MediaController mc= new MediaController(this);
    mc.setAnchorView(video);
    mc.setMediaPlayer(video);
    video.setMediaController(mc);  
    try
    {       
        Uri uri = Uri.parse("rtsp://184.72.239.149/vod/mp4:BigBuckBunny_115k.mov");
        video.setVideoURI(uri);
        video.start();
    }catch (Exception e)
    {
        Log.v("Video playing", e.getMessage());
    }
}   
}

php代码：

$out = '#EXTM3U'.PHP_EOL;

$out .= '#EXT-X-STREAM-INF:PROGRAM-ID=1,BANDWIDTH=491520'.PHP_EOL;

$out .= $output_video; //Video's Url.

header('Content-Type:application/octet-stream');

echo $out;

exit;

---

我修改了Mark的答案，以使用最新的Apache HttpComponents：

import java.io.IOException;
import org.apache.http.Header;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.client.config.RequestConfig;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClientBuilder;
import org.apache.http.protocol.BasicHttpContext;
import org.apache.http.protocol.HttpContext;
// ...
    private static String resolveRedirect(String url) throws IOException {
        RequestConfig config = RequestConfig.custom().setRedirectsEnabled(false).build();

        CloseableHttpClient httpClient = HttpClientBuilder.create().setDefaultRequestConfig(config).build();

        HttpGet httpget = new HttpGet(url);
        HttpContext context = new BasicHttpContext();

        HttpResponse response = httpClient.execute(httpget, context);

        // If we didn't get a '302 Found' we aren't being redirected.
        if (response.getStatusLine().getStatusCode() != HttpStatus.SC_MOVED_TEMPORARILY)
        {
            throw new IOException(response.getStatusLine().toString());
        }

        Header loc[] = response.getHeaders("Location");
        return loc.length > 0 ? loc[0].getValue() : null;
    }
// ...