Php 从Twitter搜索API解析trends.json

正在努力从中解析此JSON响应

使用

foreach（$json\u output->trends[0]作为$trend）
{
echo$trend->name；
}

stdClass Object ( [trends] => stdClass Object ( [2011-05-03 17:43:42] => Array ( [0] => stdClass Object ( [query] => TeAmamosLuanS [events] => [promoted_content] => [name] => TeAmamosLuanS ) [1] => stdClass Object ( [query] => CASEY RULES [events] => [promoted_content] => [name] => CASEY RULES ) [2] => stdClass Object ( [query] => Rashard Mendenhall [events] => [promoted_content] => [name] => Rashard Mendenhall ) [3] => stdClass Object ( [query] => Alexandre Nardoni [events] => [promoted_content] => [name] => Alexandre Nardoni ) [4] => stdClass Object ( [query] => Henrique Capriles [events] => [promoted_content] => [name] => Henrique Capriles ) [5] => stdClass Object ( [query] => LivroRestart [events] => [promoted_content] => [name] => LivroRestart ) [6] => stdClass Object ( [query] => TeamXtina [events] => [promoted_content] => [name] => TeamXtina ) [7] => stdClass Object ( [query] => Howard Webb [events] => [promoted_content] => [name] => Howard Webb ) [8] => stdClass Object ( [query] => Camp Nou [events] => [promoted_content] => [name] => Camp Nou ) [9] => stdClass Object ( [query] => MTV Movie Awards [events] => [promoted_content] => [name] => MTV Movie Awards ) ) ) [as_of] => 1304444622 ) 

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请帮助进行数组/对象解析。谢谢。

您可以使用以下内容：

<?php
$json_output = json_decode(file_get_contents("http://api.twitter.com/1/trends/current.json"));
foreach ($json_output->trends as $datetime=>$vals ) {
    echo "As of $datetime the trends are:<br />";
    echo "<ul>";
    foreach($vals as $trend)
        echo "<li>{$trend->name}</li>";
    echo "</ul>";
}
?>

输出：

截至2011-05-03 22:07:58趋势 它们是：

• #一言堂
• #打开
• #pssst
• 伊恩布鲁
• 贾斯汀·比伯龙
• 波布雷·梅西
• 德里克·罗斯MVP
• 莎妮娅·吐温
• 拉沙德·门登霍尔
• 拉丁美洲