如何使用PHP对数据库中的图像进行分页?
我有一个分页代码:如何使用PHP对数据库中的图像进行分页?,php,pagination,Php,Pagination,我有一个分页代码: <?php $db_username = 'root'; // Your MYSQL Username. $db_password = ''; // Your MYSQL Password. $db_name = 'database_name_here'; // Your Database name. $db_host = 'localhost'; $conDB = mysqli_conn
<?php
$db_username = 'root'; // Your MYSQL Username.
$db_password = ''; // Your MYSQL Password.
$db_name = 'database_name_here'; // Your Database name.
$db_host = 'localhost';
$conDB = mysqli_connect($db_host, $db_username, $db_password,$db_name)or die('Error: Could not connect to database.');
// Pagination Function
function pagination($query,$per_page=10,$page=1,$url='?'){
global $conDB;
$query = "SELECT COUNT(*) as `num` FROM {$query}";
$row = mysqli_fetch_array(mysqli_query($conDB,$query));
$total = $row['num'];
$adjacents = "2";
$prevlabel = "‹ Prev";
$nextlabel = "Next ›";
$lastlabel = "Last ››";
$page = ($page == 0 ? 1 : $page);
$start = ($page - 1) * $per_page;
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total/$per_page);
$lpm1 = $lastpage - 1; // //last page minus 1
$pagination = "";
if($lastpage > 1){
$pagination .= "<ul class='pagination'>";
$pagination .= "<li class='page_info'>Page {$page} of {$lastpage}</li>";
if ($page > 1) $pagination.= "<li><a href='{$url}page={$prev}'>{$prevlabel}</a></li>";
if ($lastpage < 7 + ($adjacents * 2)){
for ($counter = 1; $counter <= $lastpage; $counter++){
if ($counter == $page)
$pagination.= "<li><a class='current'>{$counter}</a></li>";
else
$pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>";
}
} elseif($lastpage > 5 + ($adjacents * 2)){
if($page < 1 + ($adjacents * 2)) {
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++){
if ($counter == $page)
$pagination.= "<li><a class='current'>{$counter}</a></li>";
else
$pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>";
}
$pagination.= "<li class='dot'>...</li>";
$pagination.= "<li><a href='{$url}page={$lpm1}'>{$lpm1}</a></li>";
$pagination.= "<li><a href='{$url}page={$lastpage}'>{$lastpage}</a></li>";
} elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2)) {
$pagination.= "<li><a href='{$url}page=1'>1</a></li>";
$pagination.= "<li><a href='{$url}page=2'>2</a></li>";
$pagination.= "<li class='dot'>...</li>";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++) {
if ($counter == $page)
$pagination.= "<li><a class='current'>{$counter}</a></li>";
else
$pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>";
}
$pagination.= "<li class='dot'>..</li>";
$pagination.= "<li><a href='{$url}page={$lpm1}'>{$lpm1}</a></li>";
$pagination.= "<li><a href='{$url}page={$lastpage}'>{$lastpage}</a></li>";
} else {
$pagination.= "<li><a href='{$url}page=1'>1</a></li>";
$pagination.= "<li><a href='{$url}page=2'>2</a></li>";
$pagination.= "<li class='dot'>..</li>";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++) {
if ($counter == $page)
$pagination.= "<li><a class='current'>{$counter}</a></li>";
else
$pagination.= "<li><a href='{$url}page={$counter}'>{$counter}</a></li>";
}
}
}
if ($page < $counter - 1) {
$pagination.= "<li><a href='{$url}page={$next}'>{$nextlabel}</a></li>";
$pagination.= "<li><a href='{$url}page=$lastpage'>{$lastlabel}</a></li>";
}
$pagination.= "</ul>";
}
return $pagination;
}
?>
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Pagination - OTallu.com</title>
<style type="text/css">
/* For this page only */
body { font-family:Arial, Helvetica, sans-serif; font-size:13px; }
.wrap { text-align:center; line-height:21px; padding:20px; }
/* For pagination function. */
ul.pagination {
text-align:center;
color:#829994;
}
ul.pagination li {
display:inline;
padding:0 3px;
}
ul.pagination a {
color:#0d7963;
display:inline-block;
padding:5px 10px;
border:1px solid #cde0dc;
text-decoration:none;
}
ul.pagination a:hover,
ul.pagination a.current {
background:#0d7963;
color:#fff;
}
</style>
</head>
<body>
<div class="wrap">
<?php
$page = (int)(!isset($_GET["page"]) ? 1 : $_GET["page"]);
if ($page <= 0) $page = 1;
$per_page = 10; // Set how many records do you want to display per page.
$startpoint = ($page * $per_page) - $per_page;
$statement = "`records` ORDER BY `id` ASC"; // Change `records` according to your table name.
$results = mysqli_query($conDB,"SELECT * FROM {$statement} LIMIT {$startpoint} , {$per_page}");
if (mysqli_num_rows($results) != 0) {
// displaying records.
while ($row = mysqli_fetch_array($results)) {
echo $row['name'] . '<br>';
}
} else {
echo "No records are found.";
}
// displaying paginaiton.
echo pagination($statement,$per_page,$page,$url='?');
?>
</div><!-- .wrap -->
</body>
</html>
此分页代码的结果如下图所示:
但我希望它不仅在屏幕上显示数据库中的数据,而且将它们放在html img标记中,这样结果可以是每页10张简单的图片,而不仅仅是文本。看看我想要的最终结果(在photoshop中创建):
我是PHP新手,您的帮助将是无价的,谢谢。问题在于
的这句话,而循环,echo$row['name']
'代码>。您应该获取图像名称或完整的图像路径(该列中的任何内容),而不是名称。随后,您必须使用
来显示图像。因此,您的while
循环有点像这样:
while ($row = mysqli_fetch_array($results)) {
echo '<img src="/path/'.$row['ImgName'].'" alt="..." height="..." width="..." />';
}
while($row=mysqli\u fetch\u数组($results)){
回声';
}
那么任何输出“虚拟线”的东西都会输出一个
标记。非常感谢Rajdeep给出的答案和代码示例。信息技术worked@Ahmad.b1995不客气!很高兴我能帮忙。:-)