Php sweet alert(当我单击sweet alert confirm按钮时,我想将数据库状态(默认:待定)更新为confirm
这是我的sweetalert,当我单击此确认按钮时,我想更新我的数据库状态列。请帮助我,谢谢Php sweet alert(当我单击sweet alert confirm按钮时,我想将数据库状态(默认:待定)更新为confirm,php,jquery,mysql,codeigniter,Php,Jquery,Mysql,Codeigniter,这是我的sweetalert,当我单击此确认按钮时,我想更新我的数据库状态列。请帮助我,谢谢 swal({ title: 'Are you sure?', text: "You won't be able to revert this!", type: 'warning', showCancelButton: true, confirmButtonColor: '#228B22', cancelButtonColor: '#d33', co
swal({
title: 'Are you sure?',
text: "You won't be able to revert this!",
type: 'warning',
showCancelButton: true,
confirmButtonColor: '#228B22',
cancelButtonColor: '#d33',
confirmButtonText: 'Yes, confirm it!'
}).then(function () {
swal(
'Confirmed!',
'success'
)
})
您可以在回调函数中编写代码 检查下面的代码
swal({
title: 'Are you sure?',
text: "You won't be able to revert this!",
type: 'warning',
showCancelButton: true,
confirmButtonColor: '#228B22',
cancelButtonColor: '#d33',
confirmButtonText: 'Yes, confirm it!'
}).then(function () {
// write your code in the response of ajax call
$.ajax({
url:"",
success:function(resp){
swal('Confirmed!','success')
}
});
})
您可以在回调函数中编写代码 检查下面的代码
swal({
title: 'Are you sure?',
text: "You won't be able to revert this!",
type: 'warning',
showCancelButton: true,
confirmButtonColor: '#228B22',
cancelButtonColor: '#d33',
confirmButtonText: 'Yes, confirm it!'
}).then(function () {
// write your code in the response of ajax call
$.ajax({
url:"",
success:function(resp){
swal('Confirmed!','success')
}
});
})
AJAX在猜测时调用,但您需要显示更多的efforthow我可以这样做吗?这可能有助于AJAX在猜测时调用,但您需要显示更多的efforthow我可以这样做吗?这可能有帮助