Php 表单选择选项，无法正确获取值和显示文本

我试图生成一个简单的下拉列表Laravel 5，其中每个选项的值都是我的businesslocations表行的ID，显示的文本由多个列组成，数据地址1、地址2、城市取自每行

在我的控制器中

public function create()
{       
    $businesslocations = Businesslocation::where('businesslocations.business_id', '=', \Auth::user()->business_id)->get();

    return view('client.create')->with(['businesslocations' => $businesslocations]);
}

这里是我在create.blade.php中的位置

{!! Form::label('businesslocation_id', 'Business location:') !!}
@foreach($businesslocations as $key => $businesslocation)
    {!! Form::select('businesslocation_id',  $businesslocations, null, ['class' => 'form-control']) !!}
@endforeach

它以值0显示：

<label for="businesslocation_id">Business location:</label>
<select class="form-control" id="businesslocation_id" name="businesslocation_id"><option value="0">{&quot;id&quot;:&quot;3&quot;,&quot;business_id&quot;:&quot;7&quot;,&quot;address_1&quot;:&quot; &quot;,&quot;address_2&quot;:&quot; &quot;,&quot;city&quot;:&quot; &quot;,&quot;created_at&quot;:&quot;2015-07-13 15:59:19&quot;,&quot;updated_at&quot;:&quot;2015-07-13 15:59:19&quot;}</option></select>

我正在为每个选项寻找类似于value=id和display text=address\u 1 address\u 2 city的内容。不确定到达那里的语法

<label for="businesslocation_id">Business location:</label>
<select class="form-control" id="businesslocation_id" name="businesslocation_id"><option value="1">Business location 1 - address_1 address_2 city</option><option value="2" selected="selected">Business location 2 - address_1 address_2 city</option></select>

---

使用常规HTML生成选项，效果很好

{!! Form::label('businesslocation_id', 'Business location:') !!}
    <select class="form-control" id="businesslocation_id" name="businesslocation_id">
    @foreach($businesslocations as $key => $businesslocation)
        <option value="{{$businesslocation->id}}">{{$businesslocation->address_1}} {{$businesslocation->address_2}} {{$businesslocation->city}}</option>
    @endforeach
    </select>

---

查询生成器可以使用lists方法—因此，如果使用返回business_id作为id，address1+address2+city作为名称的sql

SELECT `businesslocation_id` as `id`, 
CONCAT_WS(" ", `address1`, `address2`) AS `name` FROM `businesslocation`

然后返回一个列表-类似于：

$businesslocations = Businesslocation::where('businesslocations.business_id', '=', \Auth::user()->business_id)
->get()
->lists('name','id'); 
(This is untested)

然后，Eloquent将知道如何处理该名称、id，并在您坚持以下原则的情况下相应地显示：

{!! Form::select('businesslocation',  $businesslocations, null, ['id'=> 'businesslocation','class' => 'form-control']) !!}

所以基本上，如果你想用Laravel的方式来做，你需要把名字和id传递给select下拉列表

也就是说，您还可以在businesslocation模型中添加一个功能：

public function getFullAddressAttribute()
{
    return $this->business->address1 . ' ' . $this->business->address2 . ' ' . $this->business->city;
}

然后

$businesslocations = Businesslocation::where('businesslocations.business_id', '=', \Auth::user()->business_id)
->get()
->lists('fullAddress','id'); 

希望这能引导你朝着正确的方向前进！请注意，我还没有测试上面的代码