PHP preg_匹配如何在下划线之间grep字符串

我有这个字符串：

mctrn\u 25595\u advandsurtree

我们要对它进行解析，将数字

25595

提取到一个变量中，基本上将

25595\uu

后面的任何内容提取到另一个变量中

$scriptBasename = $_SERVER['SCRIPT_FILENAME'];
$scriptBasename = basename($scriptBasename);
$cuttedName = preg_replace( '/^mctrn_/', '' , $scriptBasename );
$port= preg_match('/[0-9]+/','',$scriptBasename);
$serverName= preg_match('/_"(.*)/','',$cuttedName);

echo($scriptBasename."\r\n"); 
echo($port."\r\n"); 
echo($serverName."\r\n");

命令行中的结果：

php mctrn_25595_AdvandSurthree.php  <<< script filename!
PHP Notice:  Array to string conversion in /home/bent/Downloads/mctrn_25595_AdvandSurthree.php on line 8
Array
0
0

---

php mctrn_25595_advandsurtree.php如果您知道字符串总是以mctrn_u[一些整数]u[文本字符串]的形式出现，那么您可以使用和：

否则，如果仍要使用，则可以尝试以下方法：

$scriptBasename = $_SERVER['SCRIPT_FILENAME'];
$scriptBasename = basename($scriptBasename);
preg_match('#\_(\d+)+\_(\w+)#',$scriptBasename,$matches);
if (count($matches) > 1) {
    $port = $matches[1];
    $serverName = $matches[2];
    echo($scriptBasename."\r\n"); 
    echo($port."\r\n"); 
    echo($serverName."\r\n");
}

非常感谢，这正是它应该如何工作的。我喜欢你给出多种解决方案的方式。
$scriptBasename = $_SERVER['SCRIPT_FILENAME'];
$scriptBasename = basename($scriptBasename);
preg_match('#\_(\d+)+\_(\w+)#',$scriptBasename,$matches);
if (count($matches) > 1) {
    $port = $matches[1];
    $serverName = $matches[2];
    echo($scriptBasename."\r\n"); 
    echo($port."\r\n"); 
    echo($serverName."\r\n");
}