Php 迭代到元素数组中,然后与任意数字相乘?

Php 迭代到元素数组中,然后与任意数字相乘?,php,arrays,Php,Arrays,如果我有一个这样的数组 [ 0 => [ 'sheet' => 'SUB-ARYA' 'int' => 1 'supplier_name' => 'TON DONG A CORPORATION' 'contract_no' => 'D606D17LS091' 'coil_no' => 'DNA07X2B419011701A' 'size' => '0.42MM X 101MM X COIL' 'ne

如果我有一个这样的数组

[
0 => [
    'sheet' => 'SUB-ARYA'
    'int' => 1
    'supplier_name' => 'TON DONG A CORPORATION'
    'contract_no' => 'D606D17LS091'
    'coil_no' => 'DNA07X2B419011701A'
    'size' => '0.42MM X 101MM X COIL'
    'net' => 4.65
    'nama_file' => 'STO SUB JKT 08082017.xlsx'
]
1 => [
    'sheet' => 'SUB-ARYA'
    'int' => 2
    'supplier_name' => 'NAM KIM STEEL JOINT STOCK COMPANY'
    'contract_no' => 'N014P17LS044'
    'coil_no' => '03NKXTL170400423/30'
    'size' => '0.70MM X 151.8MM X COIL'
    'net' => 4.944
    'nama_file' => 'STO SUB JKT 08082017.xlsx'
]
2 => [
    'sheet' => 'SUB-ARYA'
    'int' => 3
    'supplier_name' => 'TON DONG A CORPORATION'
    'contract_no' => 'D000G57LS597'
    'coil_no' => 'DNA07X2B511051718A'
    'size' => '0.42MM X 101MM X COIL'
    'net' => 4.74
    'nama_file' => 'STO SUB JKT 08082017.xlsx'
]
3 => [
    'sheet' => 'SUB-ARYA'
    'int' => 4
    'supplier_name' => 'TON DONG A CORPORATION'
    'contract_no' => 'D000G37LS377'
    'coil_no' => 'DNA10X1B422051704A'
    'size' => '0.43MM X 101MM X COIL'
    'net' => 4.65
    'nama_file' => 'STO SUB JKT 08082017.xlsx'
]
4 => [
    'sheet' => 'SUB-ARYA'
    'int' => 5
    'supplier_name' => 'TON DONG A CORPORATION'
    'contract_no' => 'D000G37LS378'
    'coil_no' => 'DNA10X2A421051713A'
    'size' => '0.43MM X 93.5MM X COIL'
    'net' => 4.72
    'nama_file' => 'STO SUB JKT 08082017.xlsx'
]
] 
请参见元素网络中的值。 有:

'net' => 4.65 // in 0 index
'net' => 4.944 // in 1 index
'net' => 4.74 // in 2 index
'net' => 4.65 // in 3 index
'net' => 4.72 // in 4 index
我需要把它们转换成整数形式

'net' => 4650 // in 0 index
'net' => 4944 // in 1 index
'net' => 4740 // in 2 index
'net' => 4650 // in 3 index
'net' => 4720 // in 4 index
如何以简单的方式创建呢? 请告知

您可以使用数组映射来执行此操作。例如:

function modify($el){
    // this trick will return whole element, instead of only modified one
    $t = $el;
    $t['net'] = $t['net'] * 1000;
    return $t;
}
$result = array_map("modify", $yourArray);

您可以通过单个foreach循环执行此操作:

foreach($yourArray as $i=>$v) {
   $yourArray[$i]['net'] *= 1000;
}
只要使用“保持简单”即可:

array_walk($yourArray, function (&$item, $key) {
    $item['net'] *= 1000;
});

提示:array_walk,times net by1000@LawrenceCherone添加您的评论作为答案-;吻:$el['net']*=1000;返回$el;-@Neodan回调必须返回$el的修改副本。该问题要求将密钥网的值更改为原始数组或生成具有相同结构的数组。