PHP类-样板文件还是继承?
免责声明:我有点像个noob,只做了不到一年的PHP,而做OO-PHP的还不到一年 我正在编写几个类,它们都有一些相同的功能。这是我的样板代码:PHP类-样板文件还是继承?,php,oop,inheritance,boilerplate,Php,Oop,Inheritance,Boilerplate,免责声明:我有点像个noob,只做了不到一年的PHP,而做OO-PHP的还不到一年 我正在编写几个类,它们都有一些相同的功能。这是我的样板代码: class ClassName { // required constructor arguments private $arg1; // optional arguments in an array. $options array specifies their names // and required types. '
class ClassName {
// required constructor arguments
private $arg1;
// optional arguments in an array. $options array specifies their names
// and required types. '' means any type.
private $options = array('option1'=>'type', 'option2'=>'');
private $option1 = 'default_value';
private $option2 = 'default_value';
/* getters and setters would go here if I wanted them */
// this would probably change after debugging
public function __toString() {
return print_r(get_object_vars($this), true);
}
public function __construct($arg1, array $options = array()) {
// set all required args
$this->arg1 = $arg1;
// cycle through $options array, check they are allowed,
// and check their type
foreach ($options as $option => $value) {
$type = $this->options[$option]; // no value = any type is OK
if (array_key_exists($option, $this->options)
&& (gettype($value) === $type || !$type)) {
$this->$option = $value;
}
}
}
// methods go here
}
我一直在使用这种格式:在数组中使用必需的参数,然后是可选的参数,使用foreach循环分配所有可选变量,将选项及其类型(我关心的主要区别是数组与非数组)指定为私有变量
检查和分配每个可选参数的foreach循环不会更改。我可以复制并粘贴它来创建新类,但我也认为这样做可能会更好,以避免重复代码:
abstract class ParentClass {
public function __toString() {
return print_r(get_object_vars($this), true);
}
protected function setOptions($options) {
foreach ($options as $option => $value) {
$type = $this->options[$option]; // no value = any type is OK
if (array_key_exists($option, $this->options)
&& (gettype($value) === $type || !$type)) {
$this->$option = $value;
}
}
}
}
class ChildClass extends ParentClass{
private $arg1;
private $arg2;
private $options = array('option1'=>'string', 'option2'=>'array');
private $option1 = 'default_value';
private $option2 = array('foo', 'bar');
public function __construct($arg1, $arg2, $options = array()) {
$this->arg1 = $arg1;
$this->arg2 = $arg2;
parent::setOptions($options);
}
}
我还没有对继承做太多的工作。这是它的一个好用途吗
谢谢 这将是继承的一个很好的用途,而且减少重复代码始终是最佳实践。将来当需要更改或出现错误时,代码修改起来就不那么麻烦了 编辑:顺便说一下,您还可以将所有的构造逻辑放在父类的构造函数中,然后在子类中重写它,并在处理完特定于类的逻辑后调用父构造函数。例如:
abstract class ParentClass {
public function __construct($options) {
foreach ($options as $option => $value) {
$type = $this->options[$option]; // no value = any type is OK
if (array_key_exists($option, $this->options)
&& (gettype($value) === $type || !$type)) {
$this->$option = $value;
}
}
}
public function __toString() {
return print_r(get_object_vars($this), true);
}
}
class ChildClass extends ParentClass{
private $arg1;
private $arg2;
private $options = array('option1'=>'string', 'option2'=>'array');
private $option1 = 'default_value';
private $option2 = array('foo', 'bar');
public function __construct($arg1, $arg2, $options = array()) {
$this->arg1 = $arg1;
$this->arg2 = $arg2;
parent::__construct($options);
}
}
啊,对。实际上,如果我不调用父构造函数,我的IDE会向我抱怨。