Php 正在尝试验证PayPal支付金额-MySQL IPN

我正在尝试验证Pay Pal订阅IPN的mc_gross变量

下面的代码不断为amount#u数据提供“Resource id#12”值。我试图验证的数字是0.05，这是用户付款时放在表中的数字。变量$id测试正确，数字（0.05）在payment_amount列中，所以我不知道为什么它不能执行此查询。我是MYSQL新手，所以我为任何明显的错误道歉

$payment_amount = mysql_real_escape_string($_POST['mc_gross']);
   $amount_data = mysql_query ("SELECT * FROM subscriber WHERE payment_amount = '$payment_amount' AND id = '$id' "); 
    if ($amount_data != $_POST['mc_gross']) {
        $errmsg .= "'mc_gross' does not match: ";
        $errmsg .= $_POST['mc_gross']."\n";
        file_put_contents(dirname(__FILE__).'/logs/ipn.log',"\n###AMOUNT Don't MATCH Amount in Database='$payment_amount' Amount in requested='$amount_data'for id '$id'###\n",FILE_APPEND); 
    }

使用

mysql\u fetch\u row（）

获取$amount\u数据。mysql\u query（）只返回资源id

$amount_data = mysql_query ("SELECT * FROM subscriber WHERE payment_amount = '$payment_amount' AND id = '$id' "); 
$row = mysql_fetch_row($amount_data);

echo $row[0]; 

检查链接

这是有效的：

$payment_amount = mysql_real_escape_string($_POST['mc_gross']);
    //$amount = mysql_query ("SELECT payment_amount FROM subscriber WHERE id = '$id'");
    $amount_data = mysql_query ("SELECT * FROM subscriber WHERE payment_amount = '$payment_amount' AND id = '$id' "); 
    $row = mysql_fetch_row($amount_data);
    if ($row[6] != $_POST['mc_gross']) {
        $errmsg .= "'mc_gross' does not match: ";
        $errmsg .= $_POST['mc_gross']."\n";
        file_put_contents(dirname(__FILE__).'/logs/ipn.log',"\n###AMOUNT Don't MATCH Amount in Database='$row[6]' Amount in requested='$payment_amount' for id '$id'###\n",FILE_APPEND); 
    }

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但这将返回一个数组。我不能选择付款金额和id汇合的单元格吗？@user1390395 print\u r（$amount\u data）并发布结果