Php 使用select语句时出现MySQL语法错误

嗨，你能帮我一下吗？我不知道我的错误在哪里。 这是我的密码：

    $capacitance =@mysql_query ("SELECT DISTINCT wwpn,  SUBSTR(val, 1, LENGTH(val) / 2) as capacitor,
                             SUBSTR(val, LENGTH(val) / 2+1) as capasitance
                             FROM   bom_csv where boardnumber ='$board' and qty<>'' and qty !='qty'");
    @mysql_query($capacitance,$connect)or die("Failed to execute query:<br />" . mysql_error(). "<br />" . mysql_errno());
    while($row = mysql_fetch_array($capacitance))
     {
         $capacitor = $row['capacitor'];
         $capacitance =$row['capasitance'];
         $adi_pn = $row['wwpn'];
     }

您的第一个mysql_查询将返回一个资源a resultset并将其分配给$capacity。当您在下一行再次执行mysql_查询时，资源$capacity将转换为字符串-可能是资源4-这不是一个正确的SQL

还要注意的是，不去我的学校不一定是真的：正确地避开你的字符串

$capacitance = @mysql_query ("SELECT DISTINCT wwpn,  SUBSTR(val, 1, LENGTH(val) / 2) as capacitor,
                             SUBSTR(val, LENGTH(val) / 2+1) as capasitance
                             FROM   bom_csv where boardnumber ='" . mysql_real_escape_string($board) . "' and qty<>'' and qty !='qty'", $connect)
or die("Failed to execute query:<br />" . mysql_error(). "<br />" . mysql_errno());
while ...

---

请出示您的相关PHP代码您是否尝试过在phpmyadmin中使用它？

$capacitance = @mysql_query ("SELECT DISTINCT wwpn,  SUBSTR(val, 1, LENGTH(val) / 2) as capacitor,
                             SUBSTR(val, LENGTH(val) / 2+1) as capasitance
                             FROM   bom_csv where boardnumber ='" . mysql_real_escape_string($board) . "' and qty<>'' and qty !='qty'", $connect)
or die("Failed to execute query:<br />" . mysql_error(). "<br />" . mysql_errno());
while ...