Php 如何在Guzzle中链接两个http请求

我有两个http请求

通过mailchimp api创建新列表（将创建列表id）

将新成员添加到新创建的列表中

我对将它们链接在一起的语法有点困惑。 完整代码如下。这样做对吗

<?php

// auto load
require 'vendor/autoload.php';

use GuzzleHttp\Psr7\Request;

// opt
$option = array(
  'base_uri' => "https://us12.api.mailchimp.com/3.0/",
  'auth' => ['apikey', '292bae37c631ac3ba03ed0640b44e6c3'],
);

// client
$client = new \GuzzleHttp\Client($option);

// data for a new list
$data_list = array(
  "name" => "test_mailchimp",
  "contact" => array(
    "company" => "MailChimp",
    "address1" => "675 Ponce De Leon Ave NE",
    "address2" => "Suite 5000",
    "city" => "Atlanta",
    "state" => "GA",
    "zip" => "30308",
    "country" => "US",
    "phone" => "12345678",
  ),
  "permission_reminder" => "You're receiving this email because you signed up for updates.",
  "use_archive_bar" => true,
  "campaign_defaults" => array(
    "from_name" => "test",
    "from_email" => "test@test.com",
    "subject" => "test_subject",
    "language" => "en",
  ),
    "notify_on_subscribe" => "",
    "notify_on_unsubscribe" => "",
    "email_type_option" => true,
    "visibility" => "pub",
);


// member data
$data_member = array(
  'email_address' => 'member@member.com',
  "status" => "subscribed"
);



// common
$headers = array(
  'User-Agent' => 'testing/1.0',
  'Accept'     => 'application/json'
);



// ------------- create a list -------------------
// $data should match up the field, no json =>
$url_display_list = 'lists';
$req_create_list = new Request('POST', $url_display_list, $headers, json_encode($data_list));

// promise
$promise_create_list = $client
  ->sendAsync($req_create_list)
  ->then(function ($res) use ($headers, $data_member, $client) {
    $obj = json_decode($res->getBody());
    $list_id = $obj->id;

    // --------- add a member to list ---------
    $url_create_member = 'lists/'. $list_id. '/members';
    $req_create_member = new Request('POST', $url_create_member, $headers, json_encode($data_member));

    $promise_create_member = $client
      ->sendAsync($req_create_member)
      ->then(function ($res) use ($list_id) {
        $obj = json_decode($res->getBody());
        $member_id = $obj->id;

        echo "\n--- list id ----\n";
        echo "\n". $list_id. "\n";

        echo "\n--- member id ----\n";
        echo "\n". $member_id. "\n";

        // ------------ update a member ---------


      });

  });


$promise_create_list->wait();
$promise_create_member->wait();

---

要创建一系列操作，只需从
->then（）
回调返回一个新承诺即可

$finalPromise = $client->sendAsync('POST', $url1)->then(function (Response $response1) use ($client) {
    // Do something with the first response and prepare the second query.

    $secondPromise = $client->sendAsync('POST', $url2)->then(function (Response $response2) {
        // Decode JSON and/or do other stuff with the final results.

        return json_decode($response2->getBody()->getContents(), true);
    });

    return $secondPromise;
});

// The decoded JSON from the second query here.
$response2 = $finalPromise->wait();

或者您可以使用协同程序样式（我认为它不太为人所知，但更具可读性）：

要创建一系列操作，只需从
->then（）
回调返回一个新的承诺

$finalPromise = $client->sendAsync('POST', $url1)->then(function (Response $response1) use ($client) {
    // Do something with the first response and prepare the second query.

    $secondPromise = $client->sendAsync('POST', $url2)->then(function (Response $response2) {
        // Decode JSON and/or do other stuff with the final results.

        return json_decode($response2->getBody()->getContents(), true);
    });

    return $secondPromise;
});

// The decoded JSON from the second query here.
$response2 = $finalPromise->wait();

或者您可以使用协同程序样式（我认为它不太为人所知，但更具可读性）：

我使用的是PHP7.0.15CLI，似乎没有协同程序。我需要安装什么吗？不，协同程序是Guzzle库的一部分（它是一个常用函数）。只需将其用作
\GuzzleHttp\Promise\coroutine（）
或导入（
使用函数GuzzleHttp\Promise\coroutine
）。我使用的是PHP7.0.15 cli，似乎没有coroutine。我需要安装什么吗？不，协同程序是Guzzle库的一部分（它是一个常用函数）。只需将其用作
\GuzzleHttp\Promise\coroutine（）
或导入它（
使用函数GuzzleHttp\Promise\coroutine
）。