Php 安排勾选框的问题

我正在做一个PHP表单，需要填写字段-在表单提交后，有一个关于在应用程序表单中编辑字段的部分

技能集在原始页面中打勾，但在编辑技能集时，我键入的代码显示的复选框排列顺序与原始页面不同

这是原始应用程序页面，在选中复选框之后，但在提交和可能编辑表单之前，该页面带有复选框：

如果申请者想要编辑字段，那么在服务器将字段提交并处理到数据库中之后，这里是应用程序页面。他们完全乱了！

我希望第二个图像生成一个复选框列表，就像应用程序运行时的第一个一样

字段从名为skillset的数据库表中选择或检索，并与从该表插入另一个名为emprecords的表中的值进行比较。通过在emprecords表中运行for循环，我能够回显或打印技能集列表（在emprecords数据库中用逗号分隔每个技能的字符串内爆后）特定申请人已插入，但我无法按照数组中技能列表的正确顺序打印所选复选框。我希望上面的图片会有所帮助。 以下是页面的PHP代码，用于编辑网站上申请人的字段：

<br><br><H2 align="center">SKILLS SET</H2>
<br>
<label for="skills" size="3">Pick Your Skill(s): </label>
<br><br>
<tr>

<table border='1' cellspacing='0'>
    <colgroup>
        <col span='1'>
    </colgroup>
    <tr>
        <td>Engineering Services</td>
        <td>Information Technologies</td>
    <tr>
        <td valign="top">
        <?php

        $id = $_GET["id"];

        $query2 = "SELECT * FROM emprecords WHERE id ='$id'";
        $record_set2 = $dbs->prepare($query2);
        $record_set2 -> execute();
        $row2 = $record_set2->fetch(PDO::FETCH_ASSOC);
        $sk = $row2['skills'];
        $skills1 = explode(",", $sk);
        for ($i=0; $i< count($skills1); $i++) {
            echo "<input type='checkbox' id='skills' name='skills[]' value='$skills1'checked>$skills1[$i]<br>"; 
        }

        $list = "
        SELECT *
        FROM skillsset
        WHERE category='Engineering'
        ORDER BY skills ASC";
        $listAHI = $dbs ->prepare($list);
        $listAHI -> execute();

        if(!isset($_POST['submitd'])) {
            while($row = $listAHI ->fetch(PDO::FETCH_ASSOC))
            {
                $skills = $row["skills"];
                echo "
                <form action='' method='post'>
                <input type='checkbox' id='skills' name='skills[]' value='$skills'>  $skills<br> ";
            }
        }
        else {
            while($row = $listAHI ->fetch(PDO::FETCH_ASSOC)) {
                $skills = $row["skills"]; 
                if(strlen($skills)>0){
                    if(isset($_POST['skills']) and in_array($skills, $_POST['skills'])) {
                        echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' checked>$skills<br>";
                    }
                    if(isset($_POST['skills']) and !in_array($skills, $_POST['skills'])){
                        echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
                    } else {
                        if(!in_array($skills, $_POST['skills'])) {
                            echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
                        } 
                    }
                }
                echo "</form>";
            }
        }
        ?>
        </td>
        <td valign="top">
        <?php
        $list = "
        SELECT *
        FROM skillsset
        WHERE category='Information'
        ORDER BY skills ASC";
        $listAHI = $dbs ->prepare($list);
        $listAHI -> execute();


        if(!isset($_POST['submitd'])){
            while($row = $listAHI ->fetch(PDO::FETCH_ASSOC))
            {
                $skills = $row["skills"];
                echo "
                <form action='' method='post'>
                <input type='checkbox' id='skills' name='skills[]' value='$skills'>  $skills<br> ";

            }
        }
        else {
            while($row = $listAHI ->fetch(PDO::FETCH_ASSOC)) {
                $skills = $row["skills"];
                if(strlen($skills)>0) { 
                    if(isset($_POST['skills']) and in_array($skills, $_POST['skills'])) {

                    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' checked>$skills<br>";
                    }
                    if(isset($_POST['skills']) and !in_array($skills, $_POST['skills'])) {

                    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
                    } else {
                        if(!in_array($skills, $_POST['skills'])){
                            echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
                        }
                    }
                }
                echo "</form>";
            }
        }
        ?>
        </td>
    </tr>
</table>

技能集


选择您的技能：



工程服务
信息技术
强制性链接：

让我们从小事做起

您可能需要将
技能集
更改为
技能集
（请参阅？从小开始：）

在信息技术之后，您缺少一个结束语

您正在这样做：

if(!isset($_POST['submitd'])) {
    while($row = $listAHI ->fetch(PDO::FETCH_ASSOC))
    {
        $skills = $row["skills"];
        echo "
        <form action='' method='post'>
        <input type='checkbox' id='skills' name='skills[]' value='$skills'>  $skills<br> ";
    }
}
else ...

另外，不清楚下面的代码做了什么，我花了几次阅读才明白。我对自己这样做感到内疚，但我想建议您在代码复杂时尝试并评论代码的意图

if(isset($_POST['skills']) and in_array($skills, $_POST['skills'])) {
    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' checked>$skills<br>";
}
if(isset($_POST['skills']) and !in_array($skills, $_POST['skills'])) {
    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
} else if(!in_array($skills, $_POST['skills'])) {
        echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
    } 
}

愿意而且能干！你会注意到它并没有出现问题，而是出现了两次。。。
emprecords
是否存储属于id的技能？如果你想得到答案，就回答这个问题。而且，你的表格令人不安地乱七八糟。为什么打印这么多表单却从不关闭它们？你只需要一张表格吗？你可能只需要一张表格……是的，emprecords存储属于它从skillsset表中检索到的id的技能，并将其插入emprecords表中…是的，我只需要一个表单…仍然需要找出如何只打印一次…ThnxEmpRecords是将一个人的所有技能保存在一行中，还是每个技能有一行？（因此，对于图片中的示例，是返回3行还是1行？）并将表单echo移到while循环之外、if语句之外，然后在表中停留。在任何情况下，当您循环查看emprecords的结果时，将$id拥有的所有技能存储在一个一维数组中，然后在循环查看
skillset
表的结果时，您应该检查
$skills
是否位于\u数组（$skill，$arrayContainingEmprecordsResults）

中。每次都这样做，不管是否提交。一天结束时（现在是清晨）会有更长的回答，这是一个磨坊的花蕾！我成功了！我通常不使用try/catch子句，但我想它在防止SQL注入时有很好的用途——必须捕获PDO错误。很好！如果这还不能完全回答您的问题，请将您的代码发布给其他人！它确实工作得很好…你给我的代码就是我正在使用的…虽然我可以简化它很多…但我想现在已经足够好了

if(isset($_POST['skills']) and in_array($skills, $_POST['skills'])) {
    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' checked>$skills<br>";
}
if(isset($_POST['skills']) and !in_array($skills, $_POST['skills'])) {
    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
} else if(!in_array($skills, $_POST['skills'])) {
        echo "<input type='checkbox' id='skills' name='skills[]' value='$skills' unchecked>$skills<br>";
    } 
}

$id = $_GET["id"];

$query2 = "SELECT * FROM emprecords WHERE id ='$id'";
$record_set2 = $dbs->prepare($query2);
$record_set2 -> execute();
$row2 = $record_set2->fetch(PDO::FETCH_ASSOC);
$sk = $row2['skills'];
$skills1 = explode(",", $sk);
for ($i=0; $i< count($skills1); $i++) {
    echo "<input type='checkbox' id='skills' name='skills[]' value='$skills1'checked>$skills1[$i]<br>"; 
}

<br><br><H2 align="center">SKILL SET</H2>
<br>
<label>Pick Your Skill(s):</label>
<br><br>

<table border='1' cellspacing='0'>
    <colgroup>
        <col span='1'>
    </colgroup>
    <tr>
        <td>Engineering Services</td>
        <td>Information Technologies</td>
    </tr>
    <tr>
<?php
    $empSkills = array();
    if(isset($_GET['id'])) {

        $id = $_GET["id"];

        // use this try catch to catch potential errors
        try {
            // note how $query2 has :id at the end. Using ->prepare() and ->execute(with array parameter) is one good way to protect yourself from SQL injection attacks
            // also, only pull the columns that you're going to actually use
            $query2 = "SELECT skills FROM emprecords WHERE id =:id";
            $record_set2 = $dbs->prepare($query2);
            $record_set2 -> execute(array(':id'=>$id));
            $row2 = $record_set2->fetch(PDO::FETCH_ASSOC);

            $sk = $row2['skills'];
            $empSkills = explode(",", $sk);

            // always perform clean-up
            $record_set2->closeCursor();
        } catch (PDOException $e) { // always perform error checking on PDO
            // print whatever error messages you feel appropriate
            print "Error!: " . $e->getMessage() . "<br/>";
            die(); // stop executing the script on error (up to you)
        }
    }
    // CHAR_LENGTH() is a MySQL function that returns the number of characters in the string passed to it
    try {
        $list = "
        SELECT skills
        FROM skillsset
        WHERE CHAR_LENGTH(skills) > 0 AND category='Engineering'
        ORDER BY skills ASC";
        $listAHI = $dbs ->prepare($list);
        $listAHI -> execute();
        // this is a function. it is defined below
        printSkillsTd($listAHI, $empSkills);
        $listAHI->closeCursor();
    } catch (PDOException $e) {
        print "Error!: " . $e->getMessage() . "<br/>";
        die();
    }

    try {
        $list = "
        SELECT skills
        FROM skillsset
        WHERE CHAR_LENGTH(skills) > 0 AND category='Information'
        ORDER BY skills ASC";
        $listAHI = $dbs ->prepare($list);
        $listAHI -> execute();

        printSkillsTd($listAHI, $empSkills);
        $listAHI->closeCursor();
    } catch (PDOException $e) {
        print "Error!: " . $e->getMessage() . "<br/>";
        die();
    }

/**
 * This function prints out the all skills in the PDOStatement $listAHI as checkboxes. It "checks" the checkbox if the skill is in $empSkills
 */
function printSkillsTd($listAHI,$empSkills) {
    echo '
            <td valign="top">';

    while($row = $listAHI ->fetch(PDO::FETCH_ASSOC)) {
        $skill = $row['skills'];

        // note how i left out the 'id' attribute. The id attribute of an element must be unique on the entire page. You could make the `id` something like `skill_$skill` but i don't see why you would need an `id` at all from the posted code
        echo "
                <label><input type='checkbox' name='skills[]' value='$skill'";
        if(in_array($skill,$empSkills))
            echo " checked";
        echo ">$skill</label><br>";
    }

    echo '
            </td>';
}
        ?>
    </tr>
</table>