Php 从数组集中删除父级数组并合并节点

我正在从数据库生成菜单，它工作正常，但唯一的问题是，我的

父节点是
根节点，我必须从数组中删除它

Array ( [0] => Array ( [label] => ROOT [url] => Array ( [0] => category/view [id] => 1 )
    [items] => Array ( 
         [0] => Array ( [label] => DESIGNERS [url] => Array ( [0] => category/view [id] => 2 ) ) 
         [1] => Array ( [label] => WOMEN [url] => Array ( [0] => category/view [id] => 3 ) [items] => Array ( [0] => Array ( [label] => CURRENT SALES [url] => Array ( [0] => category/view [id] => 8 ) [items] => Array ( [0] => Array ( [label] => SUIT SELECTIONS [url] => Array ( [0] => category/view [id] => 10 ) ) ) ) [1] => Array ( [label] => ENDING SOON [url] => Array ( [0] => category/view [id] => 9 ) ) ) ) 
         [2] => Array ( [label] => MEN [url] => Array ( [0] => category/view [id] => 4 ) ) 
         [3] => Array ( [label] => MAKE IT YOUR OWN [url] => Array ( [0] => category/view [id] => 5 ) ) 
         [4] => Array ( [label] => CLEARANCE [url] => Array ( [0] => category/view [id] => 6 ) ) 
         [5] => Array ( [label] => OUT OF THE BOX [url] => Array ( [0] => category/view [id] => 7 ) ) ) ) )

我希望数组以
[items]=>array（）开始，如何删除父节点

所需的解决方案必须是：

Array ( 
         [0] => Array ( [label] => DESIGNERS [url] => Array ( [0] => category/view [id] => 2 ) ) 
         [1] => Array ( [label] => WOMEN [url] => Array ( [0] => category/view [id] => 3 ) [items] => Array ( [0] => Array ( [label] => CURRENT SALES [url] => Array ( [0] => category/view [id] => 8 ) [items] => Array ( [0] => Array ( [label] => SUIT SELECTIONS [url] => Array ( [0] => category/view [id] => 10 ) ) ) ) [1] => Array ( [label] => ENDING SOON [url] => Array ( [0] => category/view [id] => 9 ) ) ) ) 
         [2] => Array ( [label] => MEN [url] => Array ( [0] => category/view [id] => 4 ) ) 
         [3] => Array ( [label] => MAKE IT YOUR OWN [url] => Array ( [0] => category/view [id] => 5 ) ) 
         [4] => Array ( [label] => CLEARANCE [url] => Array ( [0] => category/view [id] => 6 ) ) 
         [5] => Array ( [label] => OUT OF THE BOX [url] => Array ( [0] => category/view [id] => 7 ) ) ) ) )

我不确定我是否理解得很好，这就是你想要的吗

$desired_array=$old_array[0]['items']

$arrayYouWant=$otherArray['items']
，或
$array=$array['items']
如果您想覆盖，我得到的是
未定义的索引：items
。这是
$otherArray[0]['items']
检查您的输入阵列我真的认为不应该在回答时确认此类问题。这一级别的问题不应提升IMO@Martijn我同意，但它在这里，所以只要没有答案，它就会一直开放。。。OP可以删除这个问题，这就是为什么这里有反对票。没有人天生聪明。我是一个初学者，我正在学习。如果你不想回答这个问题，不要那样做。没有人强迫你。@MohitBhansali我刚才回答是为了帮助你，并说你可以稍后删除你的问题，因为它会被否决。如果我不想回答，我就不会回答。（事实上，人天生聪明，但没有知识：）。除此之外，这是非常基本的阵列知识。这可以在互联网上找到。访问这些项的方式与将它们指定给变量的方式相同