drupal api返回json导致语法错误,php的json_解码函数中json格式错误
在我的drupal网站中,我使用DrupalWeb服务模块为android和php客户端提供api。这是正确返回json格式的示例api链接(),我还检查了中返回的json,这表明我的json格式是有效的 下面是从localhost返回的jsondrupal api返回json导致语法错误,php的json_解码函数中json格式错误,php,json,drupal-7,Php,Json,Drupal 7,在我的drupal网站中,我使用DrupalWeb服务模块为android和php客户端提供api。这是正确返回json格式的示例api链接(),我还检查了中返回的json,这表明我的json格式是有效的 下面是从localhost返回的json { "status": "1", "mobile_user": [ { "id": "1", "name": "saa", "phone_no": "09978784963", "
{
"status": "1",
"mobile_user": [
{
"id": "1",
"name": "saa",
"phone_no": "09978784963",
"activate_code": "",
"deposit": "0",
"created": "2015-05-29 00:00:00",
"updated": "0000-00-00 00:00:00",
"status": "1"
}
]
}
json返回在android中运行良好,我可以调用webservice api,在android中解析json返回时,一切正常,没有错误。但我无法在php中解析json返回,php中最常用的json解码方法是json_decode()函数。当我用json_last_error()检查json返回时,显示“语法错误,格式错误的json”。如果你愿意,我必须更正我的密码
谢谢
这是我调用drupal webservice的php代码
<?php
mb_internal_encoding('UTF-8');
$url = 'http://192.168.1.111/busexpress/api/v1/mobile_user_register/mobile_user_register/retrieve.json';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$jsonReturn = curl_exec($ch);
curl_close($ch);
$data = stripslashes($jsonReturn);
json_decode($data);
switch (json_last_error()) {
case JSON_ERROR_NONE:
echo ' - No errors';
break;
case JSON_ERROR_DEPTH:
echo ' - Maximum stack depth exceeded';
break;
case JSON_ERROR_STATE_MISMATCH:
echo ' - Underflow or the modes mismatch';
break;
case JSON_ERROR_CTRL_CHAR:
echo ' - Unexpected control character found';
break;
case JSON_ERROR_SYNTAX:
echo ' - Syntax error, malformed JSON';
break;
case JSON_ERROR_UTF8:
echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
break;
default:
echo ' - Unknown error';
break;
echo PHP_EOL;
}
?>
这是web服务api的代码
<?php
function api_mobile_user_register_services_resources() {
$api = array(
'mobile_user_register' => array(
'operations' => array(
'retrieve' => array(
'help' => 'Retrieves mobile user list',
'callback' => 'mobile_user_retrieve',
'access callback' => 'user_access',
'access arguments' => array('access content'),
'access arguments append' => FALSE,
'args' => array(
array(
'name' => 'fn',
'type' => 'string',
'description' => 'Function to perform',
'source' => array('path' => '0'),
'optional' => TRUE,
'default' => '0',
),
array(
'name' => 'phone_no',
'type' => 'string',
'description' => 'get user id and activate_code by phone_no',
'source' => array('param' => 'phone_no'),
'optional' => TRUE,
'default' => '0',
),
),
),
),
),
);
return $api;
}
?>
<?php
function mobile_user_retrieve($fn,$phoneNo) {
$query = db_select('mobile_users', 'n');
$query->fields('n');
$items = $query->execute()->fetchAll();
$reply= array('status' => '1','mobile_user' => $items) ;
return $reply;
}
?>
删除
$data=stripslashes($jsonReturn)代码>
这将使您的json格式错误
编辑:
第二次使用curl\u setopt($ch,CURLOPT\u头,false)代码>
您没有查看json数据中的内容,并且有标题状态,si?这篇文章解决了我的问题“@Kris Khairallah说我们必须删除不需要的字符
这是我最后的代码
<?php
mb_internal_encoding('UTF-8');
$url = 'http://localhost/busexpress/api/v1/mobile_user_register/mobile_user_register/retrieve.json';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, false);
$jsonReturn = curl_exec($ch);
curl_close($ch);
$stripresult = stripslashes(html_entity_decode($jsonReturn));
$stringLength = strlen((string)$stripresult);
for ($i = 0; $i <= 31; ++$i) {
$stripresult = str_replace(chr($i), "", $stripresult);
}
$stripresult = str_replace(chr(127), "", $stripresult);
if (0 === strpos(bin2hex($stripresult), 'efbbbf')) {
$stripresult = substr($stripresult, 3);
}
$data = json_decode($stripresult);
echo "-->". $data -> status;
switch (json_last_error()) {
case JSON_ERROR_NONE:
echo ' - No errors';
break;
case JSON_ERROR_DEPTH:
echo ' - Maximum stack depth exceeded';
break;
case JSON_ERROR_STATE_MISMATCH:
echo ' - Underflow or the modes mismatch';
break;
case JSON_ERROR_CTRL_CHAR:
echo ' - Unexpected control character found';
break;
case JSON_ERROR_SYNTAX:
echo ' - Syntax error, malformed JSON';
break;
case JSON_ERROR_UTF8:
echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
break;
default:
echo ' - Unknown error';
break;
}
echo PHP_EOL;
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;
charset=utf-8" />
</head>
<body>
<h2>Server async</h2>
<div><?php if($data -> status == 1){ echo "Successfully async data!"; }?></div>
</body>
</html>
服务器异步
谢谢是的,我把你的代码放在了php文件中,但还是出错了。哦,对不起,我脑子里想的是别的地方。对CULLOPT_标题使用false。如果您打印响应,您将单独获得它。