Php 通过解析json获得可靠的下拉菜单

Php 通过解析json获得可靠的下拉菜单,php,json,drop-down-menu,Php,Json,Drop Down Menu,我有一个类似的json,我想知道如何将以下json解析为可靠的下拉列表,用于组织、位置和建筑 json如下所示 [{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"},{"location":[{"building":["test_loc1_building1","test_loc1_building2"],"name":"test loc

我有一个类似的json,我想知道如何将以下json解析为可靠的下拉列表,用于组织、位置和建筑 json如下所示

 [{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"},{"location":[{"building":["test_loc1_building1","test_loc1_building2"],"name":"test location1"},{"building":["test_loc2_building2"],"name":"test location2"}],"name":"test Organization"}] 

你是在问如何解析JSON,还是如何设计下拉菜单的样式和脚本?我已经解析了它,但没有从JSON中获得所有位置和构建。这是我的代码