Php 执行此函数时出错

可能重复：

继续从

这就是函数，$database就是从它来的

function getSearchedUniversityTab($country, $state, $level, $degType) {
      $query = $this->db->query("SELECT `university`.`uniId`, `university`.`name`
                                FROM (`university`)
                                inner JOIN (select degCollege, degType, count(*) as cnt  from degree where `degType` =  '$degType'  group by degCollege) clg
                                ON clg.`degCollege` = `university`.`uniId` 
                                WHERE `country` =  '$country'
                                AND `state` =  '$state'");
      $result = $query->result_array();

      foreach($result as $row)
      {
        $data[] = $row;
      }
      return $data;
      $this->db->close();  
   }

---

您的

结果极有可能返回空
改为

function getSearchedUniversityTab($country, $state, $level, $degType) {
      $query = $this->db->query("SELECT `university`.`uniId`, `university`.`name`
                                FROM (`university`)
                                inner JOIN (select degCollege, degType, count(*) as cnt  from degree where `degType` =  '$degType'  group by degCollege) clg
                                ON clg.`degCollege` = `university`.`uniId` 
                                WHERE `country` =  '$country'
                                AND `state` =  '$state'");
      $result = $query->result_array();
     if(count($result) > 0 ) {
      foreach($result as $row)
      {
        $data[] = $row;
      }

      return $data;
     }else{
       return null;
     }
      $this->db->close();  
   }

如果您有错误，请将其作为问题的引用部分，这样大家都更容易阅读…您想知道什么？因为这与您的上一个问题是同一个问题，您应该更新上一个问题。@EmilVikström是的，您是对的。遗憾的是，它不再有效了…：(